Check the Solved Sample paper of Mathematics for CBSE Class 11 Annual Exams. CBSE Class 11 Maths Sample Paper 2019 is prepared by subject experts after going through the latest syllabus and paper pattern. Solutions are also provided in a very clear and detailed manner for each and every question. Mathematics is one of the challenging subjects for class 11 students. But if prepared with a little more effort and concentration then anyone can score good marks or even full marks in this subject. In Mathematics subject, students don’t need to remember much theory like in Chemistry and Physics. Instead, Students should try to clear all the basic concepts instead of rote learning.

**Why should students solve CBSE Class 11 Sample Paper?**

1. To get familiar with the pattern and difficulty level of the exam.

2. To learn new ways of managing speed and accuracy in the examination.

3. To brush up their knowledge.

**NCERT Solutions for CBSE Class 11 Mathematics: All Chapters**

**Some salient features of the CBSE Class 11 Mathematics Sample Paper, are:**

1. Based on the latest CBSE Class 11 Syllabus.

2. Questions are picked from each and every chapter.

3. The paper design is exactly similar to that of CBSE Class 11 Question Paper.

4. Detailed solutions are provided for all questions.

**General Instructions:**

1. All the questions are compulsory.

2. The questions paper consists of 29 questions divided into 4 sections A, B, C and D.

3. Section A comprises of 4 questions of 1 mark each. Section B comprises of 8 questions of 2 marks each. Section C comprises of 11 questions of 4 marks each. Section D comprises of 6 questions of 6 marks each.

4. There is no overall choice. However, an internal choice has been provided in section C and D. You have to attempt only one of the alternatives in all such questions.

5. Use of calculators is not permitted.

**CBSE Class 11 Mathematics Syllabus 2018 – 2019**

**Some sample questions from CBSE Class 11 Sample Paper 2019 are given below: **

**Question:**

If A = {1, 2, 3, 6}, B = {3, 4, 5, 7} and C = {4, 6, 7, 8}; find A ∪ B ∪ C.

**Solution:**

Given: A = {1, 2, 3, 6}, B = {3, 4, 5, 7} and C = {4, 6, 7, 8}

In union we write all elements of both sets without repeating.

∴ A ∪ B ∪ C = {1, 2, 3, 4, 5, 6, 7, 8}

**Question:**

A coin is tossed twice, what is the probability that exactly one head occurs?

**Solution:**

The sample space is S = {HH, HT, TH, TT}

Let E be the event of getting exactly one head,

∴ E = {HT, TH}

**Question:**

Find the equation of the line that cuts off equal intercepts on the coordinate axes *a* passes through the point (4, 5).

**Solution:**

Equation of a line in intercept form is

**Question:**

In a group of 130 people, 80 like cricket, 20 like both cricket and tennis. How many like tennis only and not cricket? How many like tennis?

**Solution:**

Let C and T represent the set people who like cricket and tennis respectively.

Number of people like cricket or tennis, n(C ∪ T) = 130.

Number of people likes tennis, n(C) = 80.

Number of people likes both cricket and tennis, n(C ∩ T) = 20

Use the formula

n(C ∪ T) = n(C) + n(T) - n(C ∩ T)

⇒ 130 = 80 + n(T) - 20

⇒ 130 = 60 + n(T)

⇒ 130 - 60 = n(T)

⇒ 70 = n(T)

Hence, 70 people like tennis.

Number of people like tennis only and not cricket,

⇒ n(T - C) = n(T) – n(T ∩ C)

⇒ 70 -20

⇒ 50

Thus, 50 people like only tennis.

**Question: **

The probability that a student will pass the final examination in both English and Hindi 0.5 and the probability of passing neither is 0.1. If the probability of passing the English examination is 0.75. What is the probability of passing the Hindi examination?

**Solution:*** *

Let H and *E *denote the students passing in Hindi and English examination.

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