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JEE Main Result 2019: How NTA will prepare Merit List from Percentile Scores?

The National Testing Agency (NTA) has successfully concluded JEE Main 2019 in two sessions i.e., January and April. Students who appeared for both the sessions, are now confused about the procedure to be followed by NTA for preparing JEE Main Merit List 2019. As per NTA’s notification, it will follow normalization procedure based on percentile score in JEE Main 2019. Check here the complete normalization procedure.

Apr 23, 2019 14:26 IST
    JEE Main 2019: Merti List, Normalized Score & Expected Cut-off
    JEE Main 2019: Merti List, Normalized Score & Expected Cut-off

    In JEE Main 2019 exam, 10, 25, 000 candidates appeared in April and 10, 13, 000 appeared in January, nearly 72 per cent of them being common candidates, as per NTA statistics. The National Testing Agency has already declared the JEE Main Result 2019 of January exam. A total of 15 students scored 100 NTA Score in January 2019 examination in Paper-I. Now, the AIR ranks of the candidates will be released taking into consideration better of the two NTA Scores of all candidates appeared in Jan 2019 and April 2019 examinations. Because of the exam conducted in two sessions (January and April), the National Testing Agency will follow normalization process to prepare JEE Main 2019 Merit List.  In this article, we are going to explain you the complete normalization process to be followed by the National Testing Agency in detail.

    JEE Main 2019: Expected Cut-off to Qualify the Exam - Check This Link!


    Basic Terminologies:

    Raw score:

    The row score will be calculated by NTA on the basis of the marking scheme of the examination. For each correct answer marked by the candidates 4 marks will be added, while for each incorrect answer, 1 mark will be deducted from the total score.

    Percentile Scores:

    The percentile scores will be obtained by converting the raw marks into a scale ranging from 100 to 0 for each session of examinees.

    The Percentile score will be the Normalized Score for the examination (instead of the raw marks of the candidate) and shall be used for preparation of the merit lists.

    Note:- The Percentile Scores will be calculated up to 7 decimal places to avoid bunching effect and reduce ties.

    Steps to be followed for getting JEE Main 2019 Normalised Score:

    Step 1:

    The row score of each candidate for each subject (Maths, Physics and Chemistry) will be calculated by the National Testing Agency.

    Step 2:

    The percentile scores for each of the subject and total percentile score will be calculated using the below formula:

    JEE Main 2019 Marks Normalisation

    Here, T1,M1, P1, C1 are the raw scores in Total, Mathematics, Physics, Chemistry of a candidate and T1P, M1P, P1P, C1P are the percentile scores of Total, Mathematics, Physics, Chemistry of that candidate.

    Subjects to be used for normalization:

    1. Physics
    2. Mathematics
    3. Chemistry

    Tie-breaking rules:

    (a) Candidates obtaining higher Percentile Score in Mathematics will get higher rank.

    (b) Candidates obtaining higher Percentile Score in Physics will get higher rank.

    (c) Candidates obtaining higher Percentile Score in Chemistry will get higher rank.

    (d) Candidates older in age will get higher rank.

    JEE Main 2019 Question Paper 1: Memory Based Questions and Topics


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