RRB NTPC 2021 Exam Phase-2 Memory Based Maths Questions with Answers: Check Mathematics Questions asked in RRB NTPC 2021 CBT

RRB NTPC 2021 Exam Phase-2 Memory Based Maths Questions with Answers: RRB NTPC 2021 Phase-2 CBT Exam has been commenced from 16^th January 2021 and will be conducted till 30^th January 2021 for around 27 lakh Candidates across different exam centres in India. RRB NTPC 2021 Phase-3 will be conducted from 31st Jan to 12th Feb 2021 for around 28 Lakh candidates. Computer Based Test (CBT) is being conducted for the recruitment of RRB Non-Technical Popular Categories (NTPC) 35281 Vacancies (Graduate & Under-Graduate Posts) in two shifts.  

In this article, we are going to share the important memory based General Intelligence & Mathematics section Questions as per the feedback received by the candidates who have appeared for RRB NTPC 2021 Phase-2 CBT Exam. Candidates are advised to definitely cover these questions for scoring high marks in the Exam. Let’s have a look at the Important Questions that are being covered in the RRB NTPC 2021 Exam:

1. X alone can do a piece of work in 12 days and Y alone in 16 days. X and Y undertook to do it for Rs.6400. With the help of Z, they completed the work in 6 days. How much is to be paid to Z?

a) Rs. 375

b) Rs. 400

c) Rs. 600

d) Rs. 800

Answer: (b)

Explanation:

Answer: (c)

Explanation:

3. Find out the ratio of length and the area of a rectangle if the ratio of length & perimeter of rectangle is 1:6 and the area of rectangle is 800 sq.m?

a) 1:20  

b) 2:10

c) 5:11 

d) 2:13

Answer: (a) 

Explanation: Let the length is x & perimeter be 6x

Let the breadth be B

Then 2(x + B) = 6x

x + B = 3x
B = 2x

Now

Length × breadth = area

x × 2x = 800

2x² = 800

x = 20

Hence length = 20 m

Ratio of length: area

20 : 400

1 : 20

a) 5 : 3 : 2

b) 6 : 10 : 15

c) 2 : 3 : 5

d) 15 : 10 : 6

Answer: (d)

5. A started a business investing Rs. 50,000 in 2011. In 2012, he invested an additional amount of Rs. 20,000 and B joined him with an amount of Rs. 70,000. In 2013, B invested another additional amount of Rs. 20,000 and C joined them with an amount of Rs. 70,000. What will be A’s share in the profit of Rs. 2, 10,000 earned at the end of 3 years from the start of the business in 2011? 

a) Rs. 1,00,000

b) Rs. 95,000

c) Rs. 1,20,000

d) None of these

Answer: (b)

Explanation: Ratio of A, B and C.

A: B: C = (50000 X 12 + 70000 X 12 + 70000 X 12) : (70000 X 12 + 90000) : (70000 X 12)

= 2280000: 1920000: 840000 =19: 16: 7

A’s share = Rs. (2, 10,000 × 19/42) = Rs. 95,000

6. P and Q can do a piece of work in 45 and 40 days respectively. They began the work together but P leaves after some days and Q finished the remaining work in 23 days. Then P has worked for:

a) 9

b) 21

c) 32

d) None of these

Answer: (a)

Explanation: Work done by P in one day =1/45 and by Q = 1/40

Work done by both in days = 8 + 9/360 = 17/360

Work done by Q = 9 23 = 207,

Remaining work is done by P & Q = 360 – 207/17 = 9 days.

7. If x - (1/x) = 3, then value of x³ – (1/x³) is:

a) 32

b) 36

c) 40

d) 49

Answer: (b)

Explanation:

8. (0.16)⁷/ (0.064)³ × (0.4)²=(0.4)^?

a) 5

b) 6

c) 7

d) 8

e) None of the above

Answer: c)

Explanation:

9. X, Y and Z start a business. X invests one-third of the capital, Y invests One-fourth of the capital and the rest is invested by Z. The share of Z in the total profit of Rs. 480000 is.

a) Rs. 160000 

b) Rs. 180000 

c) Rs. 240000

d) Rs. 200000 

Answer: d)

Explanation:  X : Y : Z = 1/3 : 1/4 : 5/12 = 4: 3: 5

Z’s share = 480000 X 5/12 = 200000

10. In an examination, 34% of the students failed in mathematics and 42% failed in English. If 20% of the students failed in both the subjects, then find the percentage of students who passed in both the subjects.

a) 40% 

b) 41%

c) 43%

d) 44%

Answer: d)

Explanation: Failed in mathematics, n (1) = 34

Failed in English, n (2) = 42

n (AUB) = n(1) + n (2) – n (A∩ B)

= 34 + 42- 20 = 56

Failed in either or both subjects are 56

Percentage passed = (100−56)% = 44%