WBJEE 2014 Solved Physics Question Paper – Part 10
In this article find 5 questions (#46 to #50) from WBJEE 2014 Solved Physics Question Paper. This solved paper will help students in their final level of preparation for WBJEE Exam. WBJEE is a common entrance examinations held at state level for admission to the undergraduate level engineering and medical courses in the state of West Bengal.
Find WBJEE 2014 Solved Physics Question Paper – Part 10 in this article. This paper consists of 5 questions (#46 to #50) from WBJEE 2014 Physics paper. Detailed solution of these questions has been provided so that students can match their solutions.
Importance of Previous Years’ Paper:
Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.
46. A circuit consists of three batteries of emf E1 = 1 V, E2 = 2 V and E3 = 3 V and internal resistances 1 Ω, 2 Ω and 1 Ω respectively which are connected in parallel as shown in the figure. The potential difference between points P and Q is
(A) 1.0 V
(B) 2.0 V
(C) 2.2 V
(D) 3.0 V
The batteries are connected in parallel so, the effective resistance is given as:
So, the potential difference between two point P and Q = 2 Volt
47. A solid uniform sphere resting on a rough horizontal plane is given a horizontal impulse directed through its center so that it starts sliding with an initial velocity v0. When it finally starts rolling without slipping the speed of its center is
(A) 2 v0/7
(B) 3 v0/7
(C) 5 v0/7
(D) 6 v0/7
Angular momentum will remain conserved along point of contact.
Let v be the velocity when it starts rolling without slipping the speed of its center.
48. A long conducting wire carrying a current I is bent at 120°(see figure). The magnetic field B at a point P on the right bisector of bending angle at a distance d from the bend is (μ 0 is the permeability of free space)
49. An object is placed 30 cm away from a convex lens of focal length 10 cm and a sharp image is formed on a screen. Now a concave lens is placed in contact with the convex lens. The screen now has to be moved by 45 cm to get a sharp image again. The magnitude of focal length of the concave lens is (in cm)