Institute of Banking and Personnel Selection (IBPS) will shortly conduct the Common Written Examination (CWE) for recruiting the eligible candidates to the post of Probationary Officers. IBPS PO Exam 2013 will held on 19 October 2013, 20 October 2013, 26 October 2013, and 27 October 2013. The common written examination is subdivided into 5 different sections that are Reasoning, General Awareness, English Language, Quantitative Aptitude, and Computer Knowledge.
A total of 40 questions will come in Reasoning Section of IBPS PO Exam contains different topics like Classification, Analogy, Coding Decoding, Direction Sense, Blood Relation, etc. Jagranjosh.com, renowned educational website offers study material on every topic of Reasoning to help aspirants in getting ready for the upcoming IBPS PO Exam 2013.
From the Input-Output section, a good number of questions have been asked in the previous year IBPS PO exam.
These are the problems that test your aptitude. You will be given some input and a machine (its working) using some examples. You have to study this working and accordingly process the data given to you.
In the questions related to this topic, you are expected to be the “machine”. You would be told what processing has to be done. You would be given the input, your job would be give the output in accordance to the input.
In the topic of input output there are primarily four types of operation that can be asked in a particular question. The four operations are as follows:
1. Ordering input according to given criteria, e.g. alphabetically, in increasing/decreasing order etc.
2. Mathematical Manipulations on the output which would in this case obviously be numerical. The operations could be doubling, squaring, adding.
3. Shifting or Interchanging positions of characters/alphabets/words etc., in the input according to questions e.g. ‘shift 1st character to last’ or ‘interchange 1st & last’ etc.
4. Others like making an alphabet capital, replacing alphabet by corresponding number etc.
So, which out of these is being used can be decided as:
• If words (of the input) do not change in the output after an operation, the operations is either reordering or shifting. In this case check for rearrangement first, if it is not the operations performed then check for shifting next.
• If words (of the input) do change in the output, the operation is either Mathematical (if numbers are used) or fall into category of other operations (if alphanumeric data is used).
Example 1) A computer rearranges a particular input using some operations 01, 02, 03, and 04.
Input: I have long waited for your arrival.
Step 01: arrival long have waited for your I
Step 02: long arrival waited have for I your
Step 03: Your waited arrival have for I long
Step 04: Waited your have arrival for long I
If step 4 gives “I know you will not come back” what step will have “you back I come not will know”?
Solution: Since words remain unchanged here, so this is case of either rearrangement or shifting. So, let us number each word
I = 1, have = 2, long = 3, waited = 4, for = 5, your = 6, arrival = 7
Input: 1 2 3 4 5 6 7
Step 01: 7 3 2 4 5 6 1
Step 02: 3 7 4 2 5 1 6
Step 03: 6 4 7 2 5 1 3
Step 04: 4 6 2 7 5 3 1
So, the logic being following is as follows:-
Step 01 = Swap 1st & last; 2nd & 3rd
Step 02 = Swap 1st & 2nd, last two & 3rd and 4th
Step 03 = Swap 1st & last, 2nd & 3rd.
Step 04 = 1st & 2nd, last two, & 3rd and 4th.
Since after two steps operations again repeat and hence you can guess the 5th, 6th, 7th steps.
Step 04: I know you will not come back
Step 05: back you know will not come I
Step 06: You back will know not I come
Step 07: Come will back know not I you
Step 08: Will come know back not you I
Step 09: I know come back not you will
Step 10: Know I back come not will you
Step 11: You back I come not will know
Hence step 11 is the answer.
Questions asked in Previous Year Exams
Directions (Q. 1-4): Study the following information carefully and answer the given questions: (From IBPS PO/MT Exam 2012)
A word and number arrangement machine when given an input line of words and numbers rearranges them following a particular rule in each step. The following is an illustration of input and rearrangement. (All the numbers are two-digit numbers.)
Input: tall 48 13 rise alt 99 76 32 wise jar high 28 56 barn
Step I: 13 tall 48 rise 99 76 32 wise jar high 28 56 bam alt
Step II: 28 13 tall 48 rise 99 76 32 wise jar high 56 alt barn
Step III: 32 28 13 tall 48 rise 99 76 wise jar 56 alt barn high
Step IV: 48 32 28 13 tall rise 99 76 wise 56 alt barn high jar
Step V: 56 48 32 28 13 tall 99 76 wise alt barn high jar rise
Step VI: 76 56 48 32 28 13 99 wise alt barn high jar rise tall
Step VII: 99 76 56 48 32 28 13 alt barn high jar rise tall wise And Step VII is the last step of the above input, as the desired arrangement is obtained.
As per the rules followed in the above steps, find out in each of the following questions the appropriate step for the given input.
Input: 84 why sit 14 32 not best ink feet 51 27 vain 68 92 (All the numbers are two-digit numbers.)
1. Which step number is the following output?
32 27 14 84 why sit not 51 vain 92 68 feet best ink
1) Step V
2) Step VI
3) Step IV
4) Step III
5) There is no such step.
2. Which word/number would be at 5th position from the right in Step V?
3. How many elements (words or numbers) are there between 'feet' and '32' as they appear in the last step of the output?
4. Which of the following represents the position of ‘why' in the fourth step?
1) Eighth from the left
2) Fifth from the right
3) Sixth from the left
4) Fifth from the left
5) Seventh from the left
Solutions (For Qns 1-4):
The machine rearranges words and numbers in the following way. Numbers are being arranged from left side with the smallest number coming first and move subsequently so that in the last step numbers are arranged in descending order. The words are arranged from right side as they appear in English alphabetical order.
Input: 84 why sit 14 32 not best ink feet 51 27 vain 68 92
Step I: 14 84 why sit 32 not ink feet 51 27 vain 68 92 best
Step II: 27 14 84 why sit 32 not ink 51 vain 68 92 best feet
Step III: 32 27 14 84 why sit not 51 vain 68 92 best feet ink
Step IV: 51 32 27 14 84 why sit vain 6892 best feet ink not
Step V: 68 51 32 27 14 84 why vain 92 best feet ink not sit
Step VI: 84 68 51 32 27 14 why 92 best feet ink not sit vain
Step VII: 92 68 84 51 32 27 14 best feet ink not sit vain why
On the basis of above Output, The answers are :
Ans 1. 5
Ans 2. 4
Ans 3. 2; 27, 14 and best
Ans 4. 3; Step IV: 51 32 27 14 84 why sit vain 68 92 best feet ink not
The position of 'why' in this step is sixth from the left end.
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