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WBJEE 2015 Solved Chemistry Question Paper – Part 2

Feb 27, 2017 17:50 IST

    Find WBJEE 2015 Solved Chemistry Question Paper – Part 2 in this article. This paper consists of 5 questions (#6 to #10) from WBJEE 2015 Chemistry paper. Detailed solution of these questions has been provided so that students can match their solutions.

    Importance of Previous Years’ Paper:

    Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

    About WBJEE Exam

    WBJEE is a common entrance examinations held at state level for admission to the Undergraduate Level Engineering and Medical courses in the State of West Bengal. The Chemistry section of WBJEE 2015 engineering entrance exam consists of 40 questions.

    WBJEE 2015, Chemistry

    47. The number of lone pair of electrons on the central atoms of H2O, SnCl2, PCl3 and XeF2 respectively, are

    (A) 2,1,1,3

    (B) 2,2,1,3

    (C) 3,1,1,2

    (D) 2,1,2,3

    Ans : (A)


    Lone pair of electrons on the central atoms of H2O is 2.

    Lone pair of electrons on the central atoms of SnCl2 is 1.

    Lone pair of electrons on the central atoms of PCl3 is 1.

    Lone pair of electrons on the central atoms of XeF2 is 3.

    WBJEE 2016 Solved Physics and Chemistry Question Paper

    48. Consider the following salts: NaCl, HgCl2, Hg2Cl2, CuCl2, CuCl and AgCl. Identify the correct set of insoluble salts in water

    (A) Hg2Cl2, CuCl, AgCl

    (B) HgCl2, CuCl, AgCl

    (C) Hg2Cl2, CuCl2, AgCl

    (D) Hg2Cl2, CuCl, NaCl

    Ans : (A)


    The ionic metal compound that are insoluble in water is called insoluble salt.

    In the above options, insoluble salts are Hg2Cl2, CuCl and AgCl.

    Hence the correct option is A.

    WBJEE 2015, Chemistry

    (A) 2

    (B) 3

    (C) 4

    (D) 5

    Ans : (C)


    Number of sp hybridized carbon atom are shown in the figure:

    WBJEE 2015, Chemistry

    So, the number of sp hybridized carbon atom is 4.

    50. For the reaction A + 2B → C, the reaction rate is doubled if the concentration of A is doubled. The rate is increased by four times when concentrations of both A and B are increased by four times. The order of the reaction is

    (A) 3

    (B) 0

    (C) 1

    (D) 2

    Ans : (C)



    Rate is doubled when concentration of ‘A’ is doubled.

    Also, rate is quadrupled when concentration of ‘A’ is raised four times. This means that there is no effect on rate of reaction when we raise the concentration of B.

     Order of reaction with respect to A is 1.

    Order of reaction with respect to B is 0.

    Total order of reaction is 1.

    Also Get:

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