Find **WBJEE 2014 Solved Mathematics Question Paper – Part 14** in this article. This paper consists of 5 questions (#66 to #70) from WBJEE 2014 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.

**Importance of Previous Years’ Paper:**

Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

**About WBJEE Exam**

WBJEE is a common entrance examinations held at state level for admission to the undergraduate level engineering and medical courses in the state of West Bengal. The Mathematics section of WBJEE 2014 engineering entrance exam consists of 80 questions.

**67.** The equation of hyperbola whose coordinates of the foci are (±8, 0) and the length of latus rectum is 24 units, is

(A) 3x^{2} – y^{2} = 48

(B) 4x^{2} – y^{2} = 48

(C) x^{2} – 3y^{2} = 48

(D) x^{2} – 4y^{2} = 48

**Correct Option: (A)**

**Sol: **

The coordinates of foci of hyperbola are (±ae, 0)

The length of latus rectum of hyperbola is 2b^{2}/a

So,

ae = 8 …(1)

Also,

2b^{2}/a = 24

So,

64 = a^{2} + 12a …(2)

From (1) and (2),

a = 48

e = 1/6

So, the equation of hyperbola is

x^{2}/16 – y^{2}/48 = 1

Or, 3x^{2} – y^{2} = 48

**68.** Applying Lagrange’s Mean Value Theorem for a suitable function f(x) in [0, h], we have

f(h) = f(0) + hf′(θh), 0 < θ < 1.

(A) 1

(B) 0

(C) 1/2

(D) 1/3

**Correct Option: (C)**

**Sol: **

We have,

f(x) = cos x

So, cos h = cos 0 + h(-sin θh)

cos h = 1 + h(-sin θh) = 1 – h sin (θh)

**WBJEE 2016 Solved Physics and Chemistry Question Paper**

(A) A singleton set

(B) Not a finite set

(C) An empty set

(D) A finite set with more than one elements

**Correct Option: (A)**

**Sol: **

**Also Get:**

**WBJEE Previous Years' Question Papers**