Study Material on Quantitative Aptitude for SSC Combined Graduate Level (Tier 1) Exam, July 2012

Jul 19, 2013, 14:33 IST

Shweta Srivastava, an expert at jagranjosh has explained the concept of Time & Distance with the help of an example to tutor aspirants preparing for SSC Combined Graduate Level Exam. She has also noted the things to remember while solving a problem based on this concept

The Questions in the Quantitative Segment are aimed to test the ability of appropriate use of numbers. The scope of the test will be computation of whole numbers, decimals, fractions & relationships between numbers; percentage & ratio, time & distance; profit, loss & discount; graphs of linear equations; basic algebraic identities; pie chart; trigonometric ratio, geometry etc.

Explaining the Concept of Time & Distance


Time and Distance Formulas relate Time, Distance and Speed. These relationships have several practical applications. It is observed that in all the Competitive Exams, questions based on the concept of Time & Distance are asked.

For example if you know the speed of any vehicle and the distance covered by that vehicle, then we can easily calculate the time taken in whole journey by using the formula of Time and Distance.
Important Formulas
 Speed =  Distance/Time ,Distance= Speed×Time, Time= Distance/Speed
 S km/hr =(s×5/18)m/sec
 S m/sec =(s×18/5)km/hr

Example:
Taj Express travelling at 5/11 of its actual speed covers 42 km in 1 hr 40 min 48 sec. Find the actual speed of the Taj Express.
Solution
Suppose the actual speed of Taj = S km/hr
Then new speed =  5/11× S
Time taken by Taj with new speed
 = 1 hr 40 min 48 sec
= 1hr+40 × 1/60 hr+48 × 1/(60×60)  [Because 1hr = 60 minutes,
                                                        1 minute =  60 Second,
                                                    & 1 minute = ( 1)/60  hr ,
                                                        1 Second =  1/60 minute ]                
                                              
= 1hr +2/3 hr + 1/75 hr
= 126/75 hrs
Now, according to the formula
New Speed × Time taken by Taj with new speed =
                                      Distance covered by Taj
 5/11 S× 126/75 = 42

 S = (42×75×11)/(126×5)

 S =55km/hr
Hence, the actual speed of the Taj Express is 55 km/hr

Points to remember about Time and Distance Segment Problems-

1. Read the units of time speed and distance carefully.
2. If the distance is given in km and the aped is in m/s then always convert the units. According to the demand of the question you can change the kilometer in to meter or m/s in to km /hr.

Jagran Josh
Jagran Josh

Education Desk

    Your career begins here! At Jagranjosh.com, our vision is to enable the youth to make informed life decisions, and our mission is to create credible and actionable content that answers questions or solves problems for India’s share of Next Billion Users. As India’s leading education and career guidance platform, we connect the dots for students, guiding them through every step of their journey—from excelling in school exams, board exams, and entrance tests to securing competitive jobs and building essential skills for their profession. With our deep expertise in exams and education, along with accurate information, expert insights, and interactive tools, we bridge the gap between education and opportunity, empowering students to confidently achieve their goals.

    ... Read More

    Get here latest School, CBSE and Govt Jobs notification and articles in English and Hindi for Sarkari Naukari, Sarkari Result and Exam Preparation. Empower your learning journey with Jagran Josh App - Your trusted guide for exams, career, and knowledge! Download Now

    Trending

    Latest Education News