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UGC NET June 2013: Question Papers with Answer Keys: Computer Science and Applications Paper III

Jargranjosh.com has arranged UGC NET June 2013: Question Papers with Answer Keys to make available to the candidates who could not appear the exam.

Oct 10, 2013 16:44 IST
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University Grants Commission organized the National Eligibility Test (NET) on 30 June 2013 at various centers across the country. This year about eight lakh candidates had registered for the test and there were 79 coordinating universities to conduct the UGC NET June 2013.

Click here for UGC NET June 2013: Question Papers: Computer Science and Applications Paper III

Click here for UGC NET June 2013: Answer Keys: Computer Science and Applications Paper III

UGC NET June 2013: Question Papers with Answer Keys: Computer Science and Applications Paper III has been arranged by the Jargranjosh.com in order to make available the same to the candidates who could not appear the UGC NET June 2013 but preparing or aspiring for the same. It is also useful for State Level Eligibility Test (SLET) of different states.

7. The “PROJECT” operator of a relational algebra creates a new table that has always
(A) More columns than columns in original table
(B) More rows than original table
(C) Same number of rows as the original table
(D) Same number of columns as the original table

8. The employee information of an Organization is stored in the relation : Employee (name, sex, salary, deptname) Consider the following SQL query Select deptname from Employee Where sex = ‘M’ group by deptname having avg (salary) > {select avg (salary) from Employee} Output of the given query corresponds to
(A) Average salary of employee more than average salary of the organization.
(B) Average salary less than average salary of the organization.
(C) Average salary of employee equal to average salary of the organization.
(D) Average salary of male employees in a department is more than average salary of the organization.

9. For a database relation R(a, b, c, d) where the domains of a, b, c, d include only the atomic values. The functional dependency a → c, b → d
holds in the following relation
(A) In 1NF not in 2NF
(B) In 2NF not in 3NF
(C) In 3NF
(D) In 1NF

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