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Here we are providing a set of most important 1 mark questions for CBSE class 9 Mathematics. All these questions have been provided with detailed solution to help students make an easy and quick preparation for the Class 9 Maths annual exam 2018.

In CBSE Class 9 Mathematics Exam 2018, section - A will comprise 6 questions of 1 mark each.

in order to track their preparedness for the final exam, students are advised to practice the important questions given here. This will help them to fine-tune their preparation. Moreover, the solution provided here give students an idea to write proper solution to each question in the exam so that they may score full marks.

**Given below are some sample questions for CBSE Class 9 Mathematics: Important 1 Mark Questions:**

**Q.** If (1, −2) is a solution of the equation 2*x* – *y *= *p*, then find the value of *p*.

**Sol.**

2*x *− *y* = *p*

Putting *x* = 1, *y* = −2, in above equation, we get:

2(1) – (−2) = *p*

⟹ *p* = 4

**Q. **If the graph of equation 2*x* + *ky* = 10*k*, intersect *x*-axis at point (2, 0) then find value of *k*.

**Sol.**

Here, 2*x* + *ky* = 10*k *...(i)

At point (2, 0), equation (i) becomes:

2(2) + *k*(0) = 10*k*

⟹ 4 = 10*k*

⟹ *k* = 10/4 = 0.4

**Q.** Find the radius of largest sphere that is carved out of the cube of side 8 cm.

**Sol.**

The largest sphere can be carved out from a cube, if we take diameter of the sphere equal to edge of the cube.

∴ Diameter of the sphere = 8 cm

Thus, radius of the sphere = 8/2 = 4 cm

**Q.** If P(E)= 0.25 what is the value of P(not E).

**Sol.**

P(E) + P(not E) = 1 [∵ Sum of the probabilities of all the elementary events is 1]

∴ 0.25 + P(not E) = 1

P(not E) = 1 − 0.25

P(not E) = 0.75

**Q.** If two parallelograms PQRS and AQRB are on the same base QR and between the same parallels QR and PB, what will be the ar (PQRS) if ar (AQRB) = 25cm?

**Sol.**

Since, area of parallelograms on the same base and between same parallels is always same,

So as parallelogram PQRS and AQRB are on the same base and between same parallels,

So, ar(PQRS) = ar(AQRB)

Since, DAQRB = 25 cm^{2}

∴ ar(PQRS) =25 cm^{2}

To get the complete set of questions, click on the following link:

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