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JEE Advanced Solved Physics Paper-1 Set X

May 12, 2017 19:43 IST

    About the examination

    IIT JEE Examination is held to give admission to various prestigious engineering colleges such as IITs, NITs and various others prestigious engineering institutions.

    This examination is held at two levels: JEE Main and JEE Advanced

    About Paper

    This JEE Advanced Solved Physics Paper-1 in this article consists of 18 questions divided into three sections. The questions in this paper have been asked from the complete syllabus.  Each question of this paper is very important from examination point of view and has been developed very carefully by Subject Experts at Jagranjosh.

    Importance of Practice Papers

    Practicing sample papers, practice papers and previous years’ question papers help in assessing your preparation and time management. It will also help in increasing your marks in examination.

    Few questions from the practice paper are given below:

    Q. A wire, which passes through the hole in a small bead, is bent in the form of quarter of a circle. The wire is fixed vertically on ground as shown in the figure. The bead is released from near the top of the wire and it slides along the wire without friction. As the bead moves from A to B, the force it applies on the wire is

    iit jee advanced

    (a) Always radially outwards

    (b) Always radially inwards

    (c) radially outwards initially and radially inwards later

    (d) radially inwards initially and radially outwards later


    Correct Option: (d)

    IIT JEE Advanced

    Q9. When an electron moves in a circular path around a stationary nucleus charge at the center,

    (a)  electric field due to the nucleus at the electron changes

    (b)  the velocity of the electron changes

    (c)  the acceleration of the electron changes

    (d) none of these

    Correct Option(s): (a), (b), (c)


    Acceleration, velocity, and electric field all charge in direction although they remain same in magnitude.

    Q14. A bob of mass m, suspended by a string of length l1 is given a minimum velocity required to complete a full circle in the vertical plane. At  the  highest  point,  it  collides  elastically  with  another  bob  of  mass  m suspended by a string of length l2, which is initially at rest.  Both the strings are mass-less and inextensible.  If  the  second  bob,  after  collision  acquires  the  minimum  speed  required  to  complete  a  full  circle  in  the vertical plane,  the ratio l1/l2


    The minimum velocity required to complete a full circle in the vertical plane by a bob of mass m, suspended by a string of length l = √5gl

    Also, the speed at highest point is given as √gl

    The initial speed of 1st bob (suspended by a string of length l1 ) is √5gl1.

    The speed of this bob at highest point will be √gl1

    When this bob collides with the other bob there speeds will be interchanged.

    √gl1 = √5gl1

    So, l1/l2 = 5

    Download Complete Solved Question Paper

    Also get,

    IIT JEE Advanced Question Paper

    IIT JEE Advanced Syllabus

    IIT JEE Advanced Practice Paper

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