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JEE Main 2017 - 2018 Solved Physics Practice Paper Set-I

Oct 18, 2017 15:51 IST
    JEE Main Examination 2018: Physics
    JEE Main Examination 2018: Physics

    After completing all the topics of any subject  i.e., Physics, Chemistry and Mathematics, all JEE aspirants should attempt practice papers to understand the pattern and difficulty level of the examination.

    After doing a lot of research on previous year papers of JEE Main, the subject experts of Physics have designed this practice paper for JEE Main Examination 2018. In this article you will get solved practice paper of Physics which will help you to know the difficulty level of the questions which can be asked in JEE Main Examination 2018. All questions are of objective type having four options out of which only one is correct.

    There are 30 questions in this practice paper of different difficulty level i.e., easy, moderate and tough. We have tried to include questions from every important topic of Physics in this paper.

    This will help you to practice the new set of questions and also to manage the time and accuracy for the coming JEE Main Entrance Examination 2018.

    JEE Main 2017 - 2018 Solved Mathematics Practice Paper Set-I

    Few sample questions from the Question Paper are given below:

    Q. The length of a vertical pole above the surface of a lake of water (n = 4/3) is 24 cm. To an under-water fish just below the water surface the tip of the pole appears to be

    (a) 18 cm above the surface   

    (b) 24 cm above the surface

    (c) 32 cm above the surface   

    (d) 36 cm above the surface

    Sol. (c)

    JEE Practice paper Solution 1

    Q. A positively charged particle is released from rest in an uniform electric field. The electric potential energy of the charge

    (a) remains a constant because the electric field is uniform

    (b) increases because the charge moves along the electric field

    (c) decreases because the charge moves along the electric field

    (d) decreases because the charge moves opposite to the electric field

    Sol. (c)

    The direction of electric field is always perpendicular to one equipotential surface maintained at high electrostatic potential to other equipotential surface maintained at low electrostatic potential. The positively charged particle experiences electrostatic force along the direction of electric field i.e., from high electrostatic potential to low electrostatic potential. Thus, the .work is done by the Electric field on the positive charge, hence electrostatic potential energy of the positive charge decreases.

    Q. In Young's double slit experiment when sodium light of wavelength 5893 A° is used, then 62 fringes are seen in the field of view. Instead, if violet light of wavelength 4358 A° is used then the number of fringes that will be seen in the field of view will be

    (a) 54

    (b) 64  

    (c) 74  

    (d) 84

    Sol. (d)

    JEE Practice paper Solution 2

    Q. Biot-Savart law indicates that the moving electrons (velocity v) produce a magnetic field B such that

    (a) B is perpendicular of

    (b) B is parallel to v

    (c) it obeys inverse cube law

    (d) it is along the line joining the electron and point of observation

    Sol. (a)

    JEE Practice paper Solution 3

    Download Complete Practice Paper

    JEE Main Examination 2018: Tips to score maximum marks in Physics

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