# NCERT Exemplar Solution for CBSE Class 10 Mathematics: Triangles (Part-IA)

This article brings you the CBSE Class 10 Mathematics chapter 6, Triangles: NCERT Exemplar Problems and Solutions (Part-IA). You will get a detailed solution for every multiple choice question form NCERT Exemplar for chapter, Triangles. These questions will prove to be very helpful while preparing for CBSE Class 10 Board Exam 2017-2018.

Here you get the CBSE Class 10 Mathematics chapter 6, Triangles: NCERT Exemplar Problems and Solutions (Part-IA). This part of the chapter includes solutions of Question Number 1 to 6 from Exercise 6.1 of NCERT Exemplar Problems for Class 10 Mathematics Chapter: Triangles. This exercise comprises only the Multiple Choice Questions (MCQs) framed from various important topics in the chapter. Each question is provided with a detailed solution.

NCERT Exemplar problems are a very good resource for preparing the critical questions like Higher Order Thinking Skill (HOTS) questions. All these questions are very important to prepare for CBSE Class 10 Mathematics Board Examination 2017-2018 as well as other competitive exams.

**Find below the NCERT Exemplar problems and their solutions for Class 10 Mathematics Chapter, Triangles:**

**Exercise 6.1**

**Multiple Choice Questions (Q. No. 1-6)**

**Question. 1 **In figure, if ∠*BAC* = 90^{o} and *AD *^* BC. *Then,

**Answer.**** (c) **

**Explanation: **

Consider the following diagram:

**Question. 2** If the Lengths of the diagonals of rhombus are 16 cm and 12 cm. Then, the Length of the sides of the rhombus is

(a) 9cm

(b) 10cm

(c) 8cm

(d) 20cm

**Answer.**** (b)*** *

**Explanation: **

Given, *AC *= 16cm and* BD* = 12cm

As the diagonals of a rhombus are perpendicular bisectors of each other.

⟹ *AO *= 8cm, *BO *= 6cm and Ð*AOB* = 90° ….(i)

Using Pythagoras theorem in right angled Δ*AOB*, w have

* AB*^{2} = *AO*^{2} + *OB*^{2}

⟹* AB ^{2}* = 8

^{2}+ 6

^{2}[Using (i)]

⟹ *AB** *= 10cm.

Thus length of each side of rhombus is 10 cm.

**Question. 3** If *D**ABC ~ **D**EDF* and D*ABC* is not similar to D*DEF*, then which of the following is not true?

(a)* BC.**EF = AC.FD*

(b)* AB.EF = AC.DE** *

(c)* BC.DE = AB.EF*

(d)*BC.**DE = AB.FD*

**Answer.**** (c)*** *

**Explanation: **

Hence, option (b) is also true.

This expression shows that sides of one triangle D*CAB* are proportional to the sides of the other triangle D*PQR* and their corresponding angles are also equal.

Therefore, D*PQR* ~ D*CAB*.

**Question. 5** In figure, two line segments *AC *and *BD* intersect each other at the point *P* such that *PA = *6cm, *PB *= 3cm, *PC *= 2.5cm, *PD = *5cm, Ð*APB = *50° and Ð*CDP *= 30°. Then, Ð*PBA* is equal to

**Answer.**** (d)**

**Explanation: **

Thus, Ð*PBA = *100° verifies the option (d).

**Question. 6** If in two triangles *DEF *and *PQR,* Ð*D* =* *Ð*Q *and Ð*R* =* **Ð**E, *then which of the following is not true?

**Answer.**** **(**b**)* *

**Explanation: **

**CBSE Class 10 Mathematics Syllabus 2017-2018**

**CBSE Class 10 NCERT Textbooks & NCERT Solutions**

**NCERT Solutions for CBSE Class 10 Maths**

**NCERT Exemplar Problems and Solutions Class 10 Science: All Chapters**