CBSE Class 12th Chapter, Haloalkanes & Haloarenes carries 4 Marks in board exam. Experts of Jagranjosh.com offer the best practice material that covers all important questions so that students will not miss any portion while preparing for board exams or competitive exams. Consider the mentioned terms/questions at the time of studying.
- Answer following with IUPAC system of nomenclature:
c) CH2 = CHCH2Br
- Write the structures for the following compounds:
a) 1-Bromo-4-sec. butyl-2-methylbenzene.
f) 1−chloro−1− (4−iodophenyl)−3, 3−dimethylbut−1−ene
g) 1−Bromo−1−chloro−1, 2, 2−trifluoroethane
- Nature of bond when halogen atom is attached to the main atom.
- Write the isomers for C5H11Cl.
- Identify all the possible monochloro structural isomers expected to be formed on free radical monochlorination of (CH3)2CHCH2CH3.
- Method of preparation of haloalkanes:
a) By electrophilic substitution
b) Sandmeyer’s reaction
c) From Alkenes
- Show the finkelstein’s reaction?
- Write structures of different dihalogen derivatives of Butane.
- Draw the structure for CH3CH2Br + NaI →
- Explain the properties of Haloalkanes:
b) Melting Point
d) Boiling Point
- Haloalkanes react with KCN to form alkyl cyanides as main product while AgCN forms isocyanides as the chief product. Explain.
- What are polar protic solvents? Give examples.
- Differentiate between inversion and racemisation?
- What do you mean by chiral and achiral atom? Differentiate with an example.
- Explain enantiomer and retention with an example?
- How is elimination different from substitution? Show with a example?
- Explain why NO2 group do not show effect at meta position?
a) Fridel-Craft Reaction
c) Wrutz-Fittig Reaction
- Although chlorine is an electron withdrawing group, yet it is ortho-, para- directing in electrophilic aromatic substitution reactions. Why?
- Give the uses of:
b) Carbon tetrachloride
- What are ambident nucleophile? Explain with an example.
- Grignard reagents should be prepared under anhydrous conditions?
- Write the structure for following:
- The treatment of alkyl chlorides with aqueous KOH leads to the formation of alcohols but in the presence of alcoholic KOH, alkenes are major products. Explain.
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