# MBA Logical Reasoning Questions & Answers – Alphanumeric Series Set-I

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Created On: Jun 23, 2016 12:12 IST

The questions from the Alphanumeric Series are often asked in the MBA entrance Exams. These questions should be practiced carefully, in order to understand the tricks involved in solving these questions

Practice the alphanumeric series questions at MBA section of jagranjoch.com to score high percentile in Logical Reasoning Section of your targeted MBA entrance exam.

Directions (1-3): Answer the questions based on the arrangement given below

1. Which of the following should replace the question mark in the below series based on the series above?

a) 468

b) A48

c) 648

d) None of these

2. What is the maximum number of times that any character appears in the sequence?

a) 3

b) 2

c) 1

d) None of these

3. What is the average of all the numbers in the sequence?

a) 6

b) 6.334

c) 6.667

d) None of these

Also Practice: CAT Logical Reasoning Questions on Alphanumeric Series

Directions (4 - 7): Study the following arrangement of the English alphabet and answer the questions given below.

U Q N K L D I M Y V B X P Z E O W T C F S J R H A G

4. Which letter is tenth to the right of the letter which is exactly the middle letter between U and W?

a) W

b)  T

c)  S

d)  None of these

5. Four of the following five are alike in a certain way based on their position in the above arrangement and hence form a group. Which one does not belong to that group?

a) YIB

b) VXM

c) SCR

d) LNI

6. Which of the following pairs of letters has as many letters between them in the above arrangement as there are between them in the English alphabet?

a) ZR

b) VO

c) OH

d) NL

7. If each letter is attached a value equal to its place value in the above arrangement starting from the left, then what will be the sum of the numbers attached to all the vowels in the arrangements?

a) 60

b) 61

c) 64

d) 65

Directions (8 - 10): What should come in the place of question mark (?) in the following series?

8. 14E, 27J, 52G, 100A, ?

a) 194N

b) 192L

c) 188N

d) 148M

9.   4, 5, 12, 39, 160, 805, ?

a) 5556

b) 4836

c) 4185

d) 5006

10. MUV, NWX, OYZ, ____, QCD

a) CMN

b) UJI

c) PAB

d) IJT

 Ques 1 Ques 2 Ques 3 Ques 4 Ques 5 Ques 6 Ques 7 Ques 8 Ques 9 Ques 10 d a c d b d c b b c

Explanation:

Explanation (1): Each part is taken alternatively from the first and last part of the original sequence with 3 characters each. Then the positions of three characters are changed in a way that the last of the three characters precede the first two characters in order. So the next part should be the three characters preceding the last three characters from the end. That is 864 and their position should be 486. So‘d’ is the correct answer.

Explanation (2): Two characters & and 8 appears thrice in the sequence.

Explanation (3): The numbers in the sequence are 6, 8, 8, 8, 6 and 4. Their average is 40/6= 6.66

Explanation (4): There are 15 letters between U and W in the given series. So, the middle letter is the eighth letter to the right of U, which is Y. Clearly, the tenth letter to the right of Y is C.

Explanation (5): In all other alternatives except (b), the second letter is two steps behind the first letter, while the third letter is four steps ahead of the second letter, in the given arrangement.

Explanation (6): N and L have just one letter between them in the given series as well as in the English alphabet.

Explanation (7):

Sum of the values of the vowels

= A + E + I + O + U

= 25 + 15 + 7 + 16 + 1 = 64

Explanation (8):

And letters are summation of the two numbers.

Explanation (9):

4 × 1 + 1 = 5

5 × 2 + 2 = 12

12 × 3 + 3 = 39

39 × 4 + 4 = 160

160 × 5 + 5 = 805

805 × 6 + 6 = 4836

Explanation (10): There are two alphabetical series here. The first series is with the first letters only: MNOPQ. The second series involves the remaining letters: UV, WX, YZ, AB, CD.

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