NCERT Exemplar Solution for CBSE Class 10 Mathematics: Coordinate Geometry (Part-IIIC)

Jul 26, 2017, 15:30 IST

In this artice you will get the class 10 Mathematics NCERT Exemplar Problems and Solutions (Part-IIIC) for chapter 7, Coordinate Geometry. This part is in continuation with Part-IIIB and contains solutions to Q. No. 15-20 from exercise 7.3 of class 10 Maths Exampler for chapter Coordinate Geometry.

Class 10 Maths NCERT Exemplar, Coordinate Geometry NCERT Exemplar Problems, NCERT Exemplar Problems, Class 10 NCERT Exemplar Here you get the CBSE Class 10 Mathematics chapter 7, Coordinate Geometry: NCERT Exemplar Problems and Solutions (Part-IIIC). This part of the chapter includes solutions of Question Number 15 to 20 from Exercise 7.3 of NCERT Exemplar Problems for Class 10 Mathematics Chapter: Coordinate Geometry. Each question is provided with a detailed but simple solution.

NCERT Exemplar Solution for CBSE Class 10 Mathematics: Coordinate Geometry (Part-IIIA)

NCERT Exemplar problems are a very good resource for preparing the critical questions like Higher Order Thinking Skill (HOTS) questions. All these questions are very important to prepare for CBSE Class 10 Mathematics Board Examination 2017-2018 as well as other competitive exams.

NCERT Exemplar Solution for CBSE Class 10 Mathematics: Coordinate Geometry (Part-IIIB)

Find below the NCERT Exemplar problems and their solutions for Class 10 Mathematics Chapter, Coordinate Geometry:

Exercise 7.3

Short Answer Type Questions (Q. No. 15-20)

Question. 15 The line segment joining the points A(3, 2) and B(5, 1) is divided at the point P in the ratio 1 : 2 and it lies on the line 3x -18y + k = 0. Find the value of k.

Solution:

Question. 17 If the points A (2, 9), B (a, 5) and C (5, 5) are the vertices of a ΔABC right angled at B, then find the values of a and hence the area of ΔABC.

Solution:

As, the points A (2, 9), B (a, 5) and C (5, 5) are the vertices of a ΔABC right angled at B.

By distance formula,

Question. 19 Find the values of k, if the points A (k + 1, 2k), B (3k, 2k + 3) and C (5k − 1, 5k) are collinear.

Solution:

If three points are collinear, then the area of triangle formed by these points is zero.

Since, the points A (k + 1,2k), B (3k, 2k + 3) and C (5k - 1, 5k) are collinear, therefore area of ΔABC = 0

Question. 20 Find the ratio in which the line 2x+ 3y -5 = 0 divides the line segment joining the points (8, -9) and (2, 1). Also, find the coordinates of the point of division.

Solution:

Let the line 2x + 3y -5 = 0 divides the line segment joining the points A (8, -9) and B (2, 1) in the ratio l : 1 at point P.