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WBJEE 2015 Solved Mathematics Question Paper – Part 1

Find WBJEE Solved Mathematics Question Paper for the year 2015. This solved paper will help students in their final level of preparation for WBJEE Exam.

Jan 24, 2017 16:00 IST
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Find WBJEE 2015 Solved Mathematics Question Paper – Part 1 in this article. This paper consists of 10 questions from WBJEE 2015 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.

About WBJEE Exam

WBJEE is a common entrance examinations held at state level for admission to the Undergraduate Level Engineering and Medical courses in the State of West Bengal. The WBJEE engineering entrance exam has two sections – Mathematics, Physics and Chemistry. The Mathematics section of WBJEE 2015 engineering entrance exam consists of 80 questions.

Importance of Previous Years’ Paper:

Previous year question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

wbjee 2015 math

(A) 10

(B) 12

(C) 8

(D) 16

Ans. (B)

Sol.

By applying L Hopital’s rule:

wbjee 2015 math

wbjee 2015 math

(A) 1

(B) 2

(C) 3

(D) -1

Ans. (B)

Sol.

wbjee 2015 math

wbjee 2015 math

wbjee 2015 math

wbjee 2015 math

(A) 1

(B) 2

(C) 3

(D) 4

Ans: (C)

Sol.

We have,

wbjee 2015 math

The graph of the above function can be shown as below:

wbjee 2015 math

So, the given equation has three real solutions.

5. Which of the following is not always true?

wbjee 2015 math

wbjee 2015 math

wbjee 2015 math

(A) 1

(B) 2

(C) – 1

(D) 0

Ans. (A)

Sol.

 Let

wbjee 2015 math

wbjee 2015 math

Ans: (A)

Sol.

Let,

wbjee 2015 math

wbjee 2015 math

wbjee 2015 math

wbjee 2015 math

Ans: (A)

Sol.

wbjee 2015 math

10. If A and B are two matrices such that AB = B and BA = A, then A2 + B2 equals

(A) 2AB

(B) 2BA

(C) A + B

(D) AB

Ans. (C)

Sol.

A2 + B2 = A.A + B.B = A (BA) + B (AB) = BA + AB = A + B

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