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IIT/JEE (Mains) 2013 Question Paper with Answer Keys

Jan 20, 2014 18:38 IST

    The pattern in which the question papers are being set for a particular subject is quite different from the manner in which the course structure is defined actually. Though the course curriculum is predefined, there are certainly some gaps between the question paper formed and the content of the course. Henceforth, students need to identify these gaps and catch up where the textbooks left off, if they want to get acquainted with the examination pattern. And, they can do it easily by checking out the questions individually subject-wise. This not only helps them prepare for exams in a better manner but also leads them to the depth which the topic should be studied with.

    An unknown alcohol is treated with the “Lucas reagent" to determine whether the alcohol is primary, secondary or tertiary. Which alcohol reacts fastest and by what mechanism:

    (1) tertiary alcohol by SN1

    (2) secondary alcohol by SN2

    (3) tertiary alcohol by SN2

    (4) secondary alcohol by SN1

    Ans.1

    The first ionization potential of Na is 5.1 eV. The value of electron gain enthalpy of Na+ will be:

    (1) -5.1 eV

    (2) -10.2 eV

    (3) +2.55 eV

    (4) -2.55 eV


    Ans.1

    The molarity of a solution obtained by mixing 750 mL of 0.5 (M) HCI with 250 mnL of 2(M)HCI will be:

    (1) 1.00M

    (2) 1.75M

    (3) 0.975M

    (4) 0.875M

    Ans.4

    Which of the following is the wrong statement?

    (1) O3 molecule is bent

    (2) Ozone is violet-black in solid state
     
    (3) Ozone is diamagnetic gas

    (4) ONCI and ONO

    Ans.4

    IIT JEE Mains 2013 Question Paper with Answer Keys

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