Class 9 Maths Chapter 2 of NCERT Book is provided here in its latest edition. Chapter 2 Polynomials is one of the important chapters that carries high weightage for the annual exam. Students must read the NCERT Book to understand the concepts of Polynomials and lay a strong foundation for exams. We have provided here the latest edition of the chapter that can be downloaded in PDF format. NCERT Solutions for this chapter can also be accessed from the link provided at the end of this article.
About Class 9 Maths Chapter 2 Polynomials
This chapter introduces you to the concept of polynomials and its different types like linear and quadratic polynomials. Various other terms like degree of a polynomial, zeroes of polynomials and factorisation are explained in a very simple manner that helps students to understand the concepts very easily.
Major topics discussed in the chapter are:
→ Polynomials in One Variable
→ Zeroes of a Polynomial
→ Remainder Theorem
→ Factorisation of Polynomials
→ Algebraic Identities
PDF download of the chapter can be accessed from the following link:
Some important points to revise from the chapter are:
• A polynomial p(x) in one variable x is an algebraic expression in x of the form p(x) = anxn + an–1xn – 1 + . . . + a2x2 + a1x + a0 , where a0 , a1 , a2 , . . ., an are constants and an ≠ 0.
• a0, a1, a2, . . ., an are respectively the coefficients of x0, x, x2, . . ., xn and n is called the degree of the polynomial.
• A polynomial of degree one is called a linear polynomial.
• A polynomial of degree two is called a quadratic polynomial.
• A real number ‘a’ is a zero of a polynomial p(x) if p(a) = 0.
• Every linear polynomial in one variable has a unique zero.
• Remainder Theorem: If p(x) is any polynomial of degree greater than or equal to 1 and p(x) is divided by the linear polynomial x – a, then the remainder is p(a).
• Factor Theorem: x – a is a factor of the polynomial p(x), if p(a) = 0. Also, if x – a is a factor of p(x), then p(a) = 0.
• (x + y + z)2 = x2 + y2 + z2 + 2xy + 2yz + 2zx
• (x + y)3 = x3 + y3 + 3xy(x + y)
• (x – y)3 = x3 – y3 – 3xy(x – y)
• x3 + y3 + z3 – 3xyz = (x + y + z)(x2 + y2 + z2 – xy – yz – zx)
Also, check the NCERT Solutions for Class 9 Maths Chapter 2 from the following link: