WBJEE 2015 Solved Chemistry Question Paper – Part 1

Find WBJEE Solved Chemistry Question Paper for the year 2015. This solved paper will help students in their final level of preparation for WBJEE Exam.

Created On: Feb 23, 2017 17:34 IST

Find WBJEE 2015 Solved Chemistry Question Paper – Part 1 in this article. This paper consists of 5 questions (#1 to #5) from WBJEE 2015 Chemistry paper. Detailed solution of these questions has been provided so that students can match their solutions.

Importance of Previous Years’ Paper:

Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

About WBJEE Exam

WBJEE is a common entrance examinations held at state level for admission to the Undergraduate Level Engineering and Medical courses in the State of West Bengal. The Chemistry section of WBJEE 2015 engineering entrance exam consists of 40 questions.

41. Match the flame colours of the alkaline earth metal salts in the Bunsen burner.

(a) Calcium          (p) brick red

(b) Strontium     (q) apple green

(c) Barium           (r) crimson

(A) a-p, b-r, c-q

(B) a-r, b-p, c-q

(C) a-q, b-r, c-p

(D) a-p, b-q, c-r

Ans : (A)


The correct flame coloration is

In Bunsen Burner,

Calcium burns as Brick Red.

Srtontium burns as Crimson Red.

Barium burns as Apple Green.

So, the correct option is A.

WBJEE 2015

Ans: (A)


WBJEE 2015

43. The atomic number of cerium (Ce) is 58. The correct electronic configuration of Ce3+ ion is

(A) [Xe]4f1

(B) [Kr]4f1

(C) [Xe]4f13

(D) [Kr]4d1

Ans: (A)


The atomic number of Xe is 54.

So, the electronic configuration of Ce is [Xe] 4f1 5d16s2

The atomic configuration of Ce3+ ion is [Xe] 4f1

WBJEE 2016 Solved Physics and Chemistry Question Paper

WBJEE 2015

Ans: (B)


 For 1, 3-butadiene at room temp there is formation of 1,4- addition product. So, the product is

WBJEE 2015

and the most stable one is (I).

So, (b) is the correct option.

WBJEE 2015

Ans: (C)


It is a substitution reaction so the product formed is:

WBJEE 2015

WBJEE Sample Question Paper Set-II

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