Indian-American girl Ananya Vinay wins 90th Scripps National Spelling Bee competition of US
As a winner, Ananya will be awarded with a USD 40000 cash prize, a trophy and other awards, including a USD 2500 US savings bond from Merriam-Webster.
Ananya Vinay, a 12-year-old Indian-American girl from California, on 1 June 2017 won the 90th Scripps National Spelling Bee competition of the United States (US). With this, Ananya became the thirteenth Indian-American in a row to win this spelling bee competition.
Ananya Vinay and another Indian-American Rohan Rajeev faced each other in the final round. Ananya won on the word 'marocain', which means fabric.
Among the other words which young participants were asked to spell were: pterygoideus, mollienisia, cinerarium and hesychast.
As a winner, Ananya will be awarded with a USD 40000 cash prize, a trophy and other awards, including a USD 2500 US savings bond from Merriam-Webster as well as trips to New York and California for televised appearances.
About Scripps National Spelling Bee competition
• The Scripps National Spelling Bee first started in 1925 when nine newspapers joined together to host the competition.
• Now, over 11 million students participate in the Spelling Bee every year.
• The winner of the Bee is awarded with USD 40000 cash prize and Scripps National Spelling Bee engraved trophy, USD 2500 US savings bond from Merriam-Webster, USD 400 of reference works From Encyclopaedia Britannica and a three-year membership to Britannica Online Premium.
• Moreover, the winner is also awarded a trip to New York City to appear on LIVE with Kelly and Ryan, a trip to Hollywood for the Champion to appear on ABC's Jimmy Kimmel Live! show.