NCERT Class 12 Physics Solutions: In the ancient system of education, there were no textbooks as such. Teachers used to teach students based on their knowledge of the subject, and students were supposed to remember that throughout their lives. Thankfully, this is not the case now. You've got well-designed and well-elaborated NCERT textbooks. These are the government-authorised textbooks used in many schools affiliated with different educational boards. NCERT books provide a variety of questions and step-by-step solutions. Students referring to NCERT books need solutions to their unsolved problems.
Read: NCERT Class 12 Physics Solutions
Read: CBSE Class 12 Physics Syllabus 2023-24
In this article, students will get solutions to NCERT Class 12 Physics Electrostatic Potential and Capacitance. This is chapter 2 of the NCERT Physics Class 12 textbook. Before referring to the below-provided solutions, it is important for students to know that NCERT has revised its textbooks and deleted some of the chapters, topics, and exercises. Thus, you should first refer to the NCERT rationalised content for Class 12 from the link below.
Read: NCERT Class 12 Rationalised Content
Electrostatic Potential and Capacitance NCERT Solutions
Q 1. Two charges 5 × 10–8 C and –3 × 10–8 C are located 16 cm apart. At what point(s) on the line joining the two charges is the electric potential zero? Take the potential at infinity to be zero.
Sol. Given:
Q1 = 5x10-8 C
Q2 = 3x10-8 C
r = 16 cm
We know potential
Let the point P be at distance x from Q1 and 16-x from Q2 where the electric potential is zero.
Solving for cancellation of potential due to given charges
Or, (5 / x) + (3 / 16-x) = 0
Or, x = 40 cm from positive charge towards negative charge on extended line.
Again, in between charges
(5 / x) + (3 / x-16) = 0
Or, x = 10 cm from positive charge towards negative charge.
Q 2. A regular hexagon of side 10 cm has a charge 5 μC at each of its vertices. Calculate the potential at the centre of the hexagon.
Sol. Given:
Six charges = 5 µC
Side of hexagon = 10 cm
Distance between center to vertex = 10 cm
Now, we know
Substituting the given values
V = (9x109).(5x10-6) / (10x10-2)
Or, V = 4.5x105 V
Since all six charges are of equal magnitude and sign, therefore
Net potential at the centre = 6x(4.5x105) = 2.7x106 V
Q 3. Two charges 2 μC and –2 μC are placed at points A and B 6 cm apart
a) Identify an equipotential surface of the system.
b) What is the direction of the electric field at every point on this surface?
Sol. Given:
Q1 = 2 µC
Q2 = -2 µC
r = 6 cm
a) Since both charges are equal and opposite, they will cancel out each other’s effect at the centre of line joining them, and the plane passing through it will have equal potential (i.e. zero).
Normal to the plane in the direction AB.
| To Get the Complete Solved Chapter, Click Here |
NCERT Rationalised Content Chapter 2: Electrostatic Potential and Capacitance
|
Chapter 2: Electrostatic Potential and Capacitance
|
81 |
2.15 Energy Stored in a Capacitor (delete only derivation) |
| 87–92 |
Exercises 2.12 to 2.36 |
|
| 102–103
|
3.7 Resistivity of Various Materials (delete Tables 3.1 and 3.2 and Carbon resistors, Colour code for carbon resistor) |
|
| 107–109 |
3.10 Combinations of Resistors – Series and Parallel |
CBSE Class 12 Physics Updated Question Paper Design 2023-24
| Typology of Questions |
Total Marks |
Approximate % |
| Remembering: Exhibit memory of previously learned material by recalling facts, terms, basic concepts, and answers. Understanding: Demonstrate understanding of facts and ideas by organising, comparing, translating, interpreting, giving descriptions, and stating main ideas. |
27 |
38 |
| Applying: Solve problems to new situations by applying acquired knowledge, facts, techniques and rules in a different way. |
22 |
32 |
| Analysing: Examine and break information into parts by identifying motives or causes. Make inferences and find evidence to support generalisations. Evaluating: Present and defend opinions by making judgments about information, validity of ideas, or quality of work based on a set of criteria. Creating: Compile information together in a different way by combining elements in a new pattern or proposing alternative solutions. |
21 |
30 |
| Total |
70 |
100 |
| Practical |
30 |
|
| Gross Total |
100 |
|
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