# SBI Clerk Important Questions 2020: 35 Questions for Reasoning Ability with Solutions

SBI Clerk Important Questions for Reasoning Ability section with detailed solutions are available here. These questions are based on latest SBI Clerk Syllabus 2020 and are expected to be asked in SBI Clerk Prelims 2020 exam.  SBI Clerk Reasoning Mock Test

SBI Clerk 2020: Reasoning Questions for SBI Clerk 2020 Prelims with detailed solutions are available here. These Questions are based on the latest SBI Clerk Syllabus 2020 and are expected to be asked in SBI Clerk Prelims 2020. The preliminary exams for SBI Clerk 2020 Recruitment (for 8000+ vacancies) are scheduled to be held in February/March 2020.

If we talk about the examination pattern of SBI Clerk Prelims 2020, then candidates need to solve 100 questions in time duration of 1 hour. There will be a fixed time (of 20 minutes) for each section. More detail about each section is given below:

 Section Name Number of Questions (Marks) Duration English Language 30 (30) 20 Minutes Numerical Ability 35 (35) 20 Minutes Reasoning Ability 35 (35) 20 Minutes Total 100 Questions (100 Marks) 1 Hour

Important Questions (or Quiz) for Reasoning Ability section are given below:

Solution 1:

Every second number is the sum of the digits of its previous number. Prefixed letter is the summation of 2nd and 3rd digit.

Solution 2:

Every term is the sum of all its previous numbers. So the last number should be 16. And prefixed letter are alternative from backward side.

Solution 3:

13+(1×3)=4

23+(2×3)=14

33+(3×3)=36

43+(4×3)=76

53+(5×3)=140

Prefixed letters are ABCDE and suffixed letters are ZYXWV.

Solution 4:

13*2-20=25

25*2-21=48

48*2-22=92

92*2-23=176

And letters are summation of the two numbers.

Solution 5:

The series is:
25 × 1 – 2 = 23
23 × 2 – 3 = 43
43 × 3 – 4 = 125
125 × 4 – 5 = 495
495 × 5 – 6 = 2469
2469 × 6 – 7 = 14807

Solution 6:

Clearly, X’s new position is 25th from the left. But this is the same as Y’s earlier position which is 9th from the right.

Then total number of girls in a row = 25+9-1 = 33.

Solution 7:

Except Investments, all others are types of comes on the liability side of the balance sheet.

Solution 8:

If every fourth alphabet is replaced by # then new series becomes:

A B C # E F G # I J K # M N O # Q R S # U V W # Y Z

Here the fourteenth element from the left is N. The ninth element to the left of N is E.

Solution 9:

(b)

Solution 10:

(d)

Solution 11:

(a)

Solution 12:

(c)

Solution 13:

(b)

Solution 14:

(a)

 `Position` `1` `2` `3` `4` `5` `6` `7` `Name` `F` `G` `B` `A` `E` `C` `D` `Colour` `Pink` `White ` `Yellow` `Blue` `Brown` `Black` `Green`

Solution 15:

(c)

Solution 16:

(b)

Solution 17:

(b)

Solution 18:

(b)

Solution 19:

(d)

M + L ÷ B × A means M is the brother of L and L is the sister of B and A is the mother of O.

Solution 20:

(c)

Solution 21:

(a)

Solution 22:

(e)

Solution 23:

(b)

Solution 24:

(c)

 Words Rupees Borrow me shares for types his to Codes ba ka ro ve di la se yo

Solution 25:

(b)

Explanation:

The shortest distance between A and D can be found out by using the Pythagoras theorem. Distance between AD = √ (92 + 122) = 15kms.

Solution 26:

(c) Explanation:
As M = L ≥ F we can say that either M = F or M > F

Solution 27:

(d)
Explanation: From the statement we get, K≥X≤Y>T. Hence neither I nor II is true.

Solution 28:

(e)
Explanation: From the statement we get X≤T<A=L, Hence L<X and T<L are definitely true.

Solution 29:

(b)
Explanation:
From the given statement we get F=M>B <L, hence F>B  is definitely true but L>F is false.

Solution 30:

(a)
Explanation:
From  the statement we get A≤C=N<F, thus A<N is false as A can also be equal to N but F>A is definitely true

Solution 31:

(b)
Explanation: As Q gets rejected; P and R should be there. Also as V is selected T cannot be there and as R is selected W cannot be there.

Solution 32:

(c)
Explanation: QT, RW, VT cannot be together hence options (a), (b) and (d) are eliminated.

Solution 33:

(b)
Explanation:
There are 2 possible combinations of four members:
P, Q, R, U and P, Q, R, V.

Solution 34:

(b)

Solution 35:

(b)

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