The chapter Atomic Structure is a very important part of Physical Chemistry in the syllabus of WBJEE Examination 2018. About 2-3 questions are always asked from this topic in WBJEE Examination.
This article will provide you complete chapter notes of chapter Atomic Structure including all important topics like atomic number, mass number, isobar, isotopes, isotones, isoelectronics, Planck equation, photoelectric effect, angular momentum, Bohr radius, Rydberg equation, De broglie principle, quantum numbers, Aufbau principle, Pauli Exclusion principle, Hund’s rule of maximum multiplicity etc. These notes are based on the latest syllabus of WBJEE Examination 2018. It will provide you complete summary of the chapter Atomic Structure. Some previous years questions are also included in this article to help students in understanding the difficulty level of the questions asked in previous year examinations of WBJEE.
About the exam:
West Bengal Joint Entrance Examination (WBJEE) is a state level common entrance test organized by West Bengal Joint Entrance Examinations Board for admission to the Undergraduate Level Engineering and Medical Courses through a common entrance test in the State of West Bengal.
WBJEE Chemistry Syllabus: 2017 - 2018
Important Concepts:
Important Questions and Preparation Tips – Solid State
Some previous years solved questions are given below:
Question 1:
The atomic number of cerium (Ce) is 58. The correct electronic configuration of Ce3+ ion is
(A) [Xe]4f1
(B) [Kr]4f1
(C) [Xe]4f13
(D) [Kr]4d1
Solution 1:
The atomic number of Xe is 54.
So, the electronic configuration of Ce is [Xe] 4f1 5d16s2
The atomic configuration of Ce3+ ion is [Xe] 4f1
Hence, the correct option is (A).
WBJEE 2014 Solved Physics Question Paper
Question 2:
The wavelength of second Balmer line in Hydrogen spectrum is 600 nm. The wavelength for its third line in Lyman series is
(A) 800 nm
(B) 600 nm
(C) 400 nm
(D) 120 nm
Solution 2:
Hence, the correct option is (D).
WBJEE 2017 Question Paper with Answer Key
Question 3:
Solution 3:
Hence, the correct option is (C).
Important Questions and Preparation Tips - Phenols
Question 4:
Ni2+ ion (Z = 28) contains unpaired electrons
(A) 1
(B) 2
(C) 3
(D) 5
Solution 4:
Hence, the correct option is (B).
Question 5:
Solution 5:
Hence, the correct option is (B).
JEE Advanced Syllabus 2018 – complete syllabus for Physics, Chemistry and Mathematics
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