AP Inter 2nd Year Maths 2A Paper Analysis 2024 with Question Paper PDF and Answer Key

AP Inter 2nd Year Maths A Question Paper 2024: The Board of Intermediate Education Andhra Pradesh (BIEAP) conducted the AP Inter 2nd Year Maths 2A exam today, March 7, 2024. The exam was scheduled from 9:00  AM to 12 noon. This article presents a detailed analysis of the AP Inter 2nd Year Maths 2A Exam 2024 along with the question paper and answer key. Students can cross-check their answers and assess their performance in the AP Inter 2nd Year Maths Exam 2024.

Pattern of AP Inter 2nd Year Maths Question Paper 2024

The question paper had a total of 24 questions and the overall weightage of the question paper was 75 marks. Students were given 3 hours to answer all questions.

The question paper was divided into three sections:

• Section A - Very Short Answer Type Questions
• Section B - Short Answer Type Questions
• Section C - Long Answer Type Questions

To qualify for the exam candidates are required to score a minimum of 35% in the exam.

AP Inter 2nd Year Maths Exam Analysis 2024

The analysis presented here is based on the students’ feedback and experts review of the paper. With this analysis we intend to present a comprehensive overview of the AP Inter 2nd Year Maths 2A Exam 2024, shedding light on the paper's difficulty level and question patterns.

Students’ Feedback About AP Inter 2nd Year Maths Exam 2024

Students seemed to be satisfied with their Maths exam today. Most of the students found the paper moderate on the difficulty level. “No question in the Maths exam was repeated from the previous years,” mentioned a student. A few students found Section C challenging while others considered Section B tricky and demanded a thorough understanding.

AP Inter 2nd Year Maths Question Paper 2024

Download the complete question paper in PDF below:

AP Inter 2nd Year Maths Answer Key 2024

SECTION A

I. Very Short Answer Type Questions.

(i)Answer all the questions.

(ii)Each question carries two marks.

1.Write the conjugate of the complex number 5i/7+i.

Answer: Conjugate 5i/7+i = 1/10 - i(7/10)

Hint: Rationalise the denominator (7+i)

2.Simplify -2i(3+i)(2+4i)(1+i) and obtain the modulus of that complex number.

Answer: Modulus = 40

Hint: Simplifying -2i(3+i)(2+4i)(1+i) gives (32+24i)

Let z = (32+24i)

Modulus of z is, |z| = √(x+y), where x is the real part and y is the imaginary part of z.

3.If 1, w, w² are the cube roots of unity, then prove that:

(2-w) (2-w²) (2-w¹⁰) (2-w¹¹)=49.

Answer: (2-w) (2-w²) (2-w¹⁰) (2-w¹¹)=49

Hint: Given, w=∛1

we have, w³−1=0.

∴ (w−1)(w²+w+1)=0

Or w²+w=−1 .........(i)

Simplify (2-w) (2-w²) (2-w¹⁰) (2-w¹¹) using (i).

4.For what values of x the expression x²-5x-14 is positive?

Answer: x²−5x−14 is positive for  x<−2 or x>7

5.Form polynominal equations of the lowest degree, with roots 1, -1, 3.

Answer: Required polynomial is :  x³ - 3x² - x + 3

Hint: Let the given roots be: α=1, β=-1,  γ=3

For a polynomial, P(x) = ax³+bx²+cx+d

α+β+γ=-b/a .........(i)

αβ+βγ+γα=c/a ......(ii)

αβγ=-d/a  .........(iii)

Solve (i), (ii) and (iii) to find a, b and c.

Then find P(x) by substituting the values of a, b and c.

6.There are 4 copies (alike) each of 3 different books. Find the number of ways of arranging these 12 books in a shelf in a single row.

Answer: Total number of ways of arranging these 12 books = 12!/(4!)²

7.If ⁿP_r=5040 and ⁿC_r=210, find n and r.

Answer:  n=10 and r=4

8.Write down and simplify 6th term in (2x/3 + 3y/2)⁹.

Answer: 6th term in (2x/3 + 3y/2)⁹ = 189x⁴y⁵

9.Find the mean deviation about the median for the following data:

4, 6, 9, 3, 10, 13, 2.

Answer: Required median = 3.29

10.The mean and variance of a binomial distribution are 4 and 3 respectively.

Fix the distribution and find P(x≥1).

Answer: P(x≥1) = 1-(3/4)¹⁶

Also Check| AP Inter 1st and 2nd Year Date Sheet 2024