Balancing of Chemical Reactions: Methods with Examples

Balancing of Chemical Equations: This article is a simple and complete guide for students to understand the ways of balancing chemical equations. Follow the easy instructions to get ready for your 2025 board exams.

Jun 20, 2024, 15:10 IST
Methods of Balancing Chemical Reactions
Methods of Balancing Chemical Reactions

Methods Of Balancing Chemical Reactions: Balancing chemical equations is an important part of writing chemical reactions accurately. It ensures that the law of conservation of mass is maintained, meaning the number of atoms of reactants is the same as the number of product atoms. Here are the three methods for balancing chemical equations:

How To Balance Chemical Equations?

There are multiple ways to balance a chemical equation. But only a few are discussed with students. The reason is to start with the basics and then understand the advanced ones. Here, three methods of balancing chemical reactions are mentioned. Let's check them one by one.

1. Inspection (Trial and Error) Method or Traditional Balancing Method

This is the most common and straightforward method, especially for simpler equations. It involves adjusting the coefficients (the numbers in front of molecules) to balance the atoms on both sides of the equation.

Steps:

  1. Write the unbalanced equation: List the reactants and products.
  2. Count the atoms of each element: Compare the number of atoms of each element on both sides of the equation.
  3. Adjust coefficients to balance one element at a time: Start with the element that appears in the least number of compounds.
  4. Re-check the balance: Ensure that the number of atoms of each element is equal on both sides.
  5. Repeat as necessary: Continue adjusting coefficients until all elements are balanced.

Example: Balancing H2+O2→H2O

  1. Write the unbalanced equation: H2+O2→H2
  2. Count atoms: 2 H and 2 O on the left, 2 H and 1 O on the right.
  3. Adjust coefficients: Place a coefficient of 2 in front of H2O to balance oxygen.

H2+O2→2H2O

  1. Re-check balance: Now, there are 2 H on the left and 4 H on the right. Adjust hydrogen by placing a coefficient of 2 in front of H2. 2H2+O2→2H2O.
  2. Equation is balanced.

2. Ion-Electron Method (Half-Reaction Method)

This method is used primarily for balancing redox (oxidation-reduction) reactions.

Steps:

  1. Separate the reaction into two half-reactions: One for oxidation and one for reduction.
  2. Balance each half-reaction:
    1. Balance all elements except hydrogen and oxygen.
    2. Balance oxygen atoms by adding H2
    3. Balance hydrogen atoms by adding H+(in acidic solution) or OH (in basic solution).
    4. Balance the charge by adding electrons (e).
  3. Combine the half-reactions: Ensure that the electrons gained and lost are equal and cancel out.
  4. Simplify the combined reaction: Ensure all elements and charges are balanced.

Example: Balancing MnO4+ Fe2+→Mn2++ Fe3+ in acidic solution.

  1. Write half-reactions:
    1. Oxidation: Fe2+→Fe3++ e
    2. Reduction: MnO4+ 8H++5e→Mn2++ 4H2O
  2. Balance each half-reaction:
    1. Oxidation is already balanced.
    2. Reduction is balanced with electrons, hydrogen, and oxygen.
  3. Combine half-reactions:
    1. Multiply the oxidation half-reaction by 5 to match electrons: 5Fe2+→5Fe3++5e
    2. Combine: 5Fe2++MnO4−+8H+→5Fe3++Mn2++4H2O5
  4. Ensure all elements and charges are balanced.

3. Algebraic Method

This method involves using algebra to solve for the coefficients. It is useful for more complex equations.

Steps:

  1. Assign algebraic variables to each coefficient: Use letters like a, b, c, etc.
  2. Write equations based on atom counts: For each element, write an equation representing the number of atoms on both sides.
  3. Solve the system of equations: Use algebraic methods to find the values of the variables.
  4. Substitute and simplify: Substitute the values back into the coefficients and simplify if necessary.

Example: Balancing C2H6+O2→CO2+H2O

  1. Assign variables: aC2H6+bO2→cCO2+dH2O
  2. Write atom balance equations:
  • For carbon (C): 2a=c
  • For hydrogen (H): 6a=2d
  • For oxygen (O): 2b=2c+d
  1. Solve equations:
    1. From 2a=c, c=2a
    2. From 6a=2d,d=3a
    3. Substitute into oxygen equation: 2b=2(2a)+3a, 2b = 4a + 3a, 2b=7, b= 7a/2​
  2. Choose a=1 for simplicity:
    1. b=7/2, c=2, d=3
  3. Substitute and balance: C2H6+7/2O2→2CO2+3H2O
  4. Clear fractions by multiplying by 2: 2C2H6+7O2→4CO2+6H2O2
Atul Rawal
Atul Rawal

Executive

Meet Atul, he is a Master of Science in the field of biotechnology. He has a counting experience in the field of Ed-tech and is proficient in content writing. Atul is a creative person and likes to color his ideas on canvas. He is a graduate of the University of Delhi in Biochemistry. Constant learning is one of his traits and he is devoted to the school section of Jagran Josh. His belief is to help students in all possible ways. He can be reached at atul.rawal@jagrannewmedia.com

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