Find WBJEE 2014 Solved Physics Question Paper – Part 3 in this article. This paper consists of 5 questions (#11 to #15) from WBJEE 2014 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.
Importance of Previous Years’ Paper:
Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.
About WBJEE Exam
WBJEE is a common entrance examinations held at state level for admission to the undergraduate level engineering and medical courses in the state of West Bengal. The Physics section of WBJEE 2014 engineering entrance exam consists of 40 questions.
Q11. A very small circular loop of radius a is initially (at t = 0) coplanar and concentric with a much larger fixed circular loop of radius b. A constant current I flows in the larger loop. The smaller loop is rotated with a constant angular speed ω about the common diameter. The emf induced in the smaller loop as a function of time t is
Q12. A drop of some liquid of volume 0.04 cm3 is placed on the surface of a glass slide. Then another glass slide is placed on it in such a way that the liquid forms a thin layer of area 20 cm2 between the surfaces of the two slides. To separate the slides a force of 16×105 dyne has to be applied normal to the surfaces. The surface tension of the liquid is (in dyne-cm–1)
Ans : (C)
Let thickness of layer be t.
Q13. A proton of mass m and charge q is moving in a plane with kinetic energy E. If there exists a uniform magnetic field B, perpendicular to the plane of the motion the portion will move in a circular path of radius
Q14. In which of the following phenomena, the heat waves travel along straight lines with the speed of light ?
(A) thermal conduction
(B) forced convection
(C) natural convection
(D) thermal radiation
In thermal radiation, the heat waves travel along straight lines with the speed of light.
Q15. An artificial satellite moves in a circular orbit around the earth. Total energy of the satellite is given by E. The potential energy of the satellite is
Let the potential energy of the satellite be PE and total energy be TE.
PE = 2(TE)
Given, TE = E
PE = 2E
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