WBJEE: Important Questions and Preparation Tips – Dual Nature of Radiation & Matter

West Bengal Joint Entrance Examination (WBJEE) is a state level common entrance test organized by West Bengal Joint Entrance Examinations Board for admission to the Undergraduate Level Engineering and Medical Courses through a common entrance test in the State of West Bengal.

Find chapter notes of chapter Dual Nature of Radiation & Matter including important topics work function, photo-electric effect work function, Einstein’s photoelectric equation, photon, wave nature of matter etc.

These notes are based on the latest syllabus of WBJEE Examination. These notes are prepared by Subject Experts of Physics after the detailed analysis of the syllabus and the pattern of previous year papers of the examination.

In these notes, important concepts, formulae and some previous year solved questions are also included which will give an idea about the difficulty level of the questions.
The concepts given in these notes are in concise form and students can be refer these notes for quick revision just before the examination.

WBJEE: Important Questions and Preparation Tips – Alternating Current

Important Concepts:

WBJEE: Important Questions and Preparation Tips – Electromagnetic Induction

WBJEE: Important Questions and Preparation Tips – Electromagnetic Induction

Some previous years solved questions are given below:

Question 1:

Solution 1:

Hence, the correct option is (C).

WBJEE: Important Questions and Preparation Tips – Magnetism

Question 2:

Solution 2:

Hence, the correct option is (D).

WBJEE: Important Questions and Preparation Tips – Electric Current

Question 3:

Solution 3:

Hence, the correct option is (B).

Question 4:

The de-Broglie wavelength of an electron is the same as that of a 50 keV X-ray photon. The ratio of the energy of the photon to the kinetic energy of the electron is (the energy equivalent of electron mass is 0.5 MeV

(A) 1 : 50

(B) 1 : 20

(C) 20 : 1

(D) 50 : 1

Solution 4:

Hence, the correct option is (C).

WBJEE: Important Questions and Preparation Tips – Electrostatics

Question 5:

A photon of wavelength 300 nm interacts with a stationary hydrogen atom in ground state. During the interaction, whole energy of the photon is transferred to the electron of the atom. State which possibility is correct? (Consider, Planck’s constant = 4 × 10^–15 eVs, velocity of light = 3 × 10⁸ m/s, ionization energy of hydrogen = 13.6eV)

(A) Electron will be knocked out of the atom

(B) Electron will go to any excited state of the atom

(C) Electron will go only to first excited state of the atom

(D) Electron will keep orbiting in the ground state of atom

Solution 5:

The energy contained in the photon of given wavelength is given by,

Putting the values given in question,

λ = 300 × 10^-9

h = 4 × 10^–15 eVs

So,

This energy is less than first excitation energy of hydrogen i.e. 10.2 eV.

So, electron will keep orbiting in its ground state.

Hence, the correct option is (D).

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