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Ding Junhui won Indian Open Snooker Title 2013

Oct 19, 2013 15:17 IST

Ding Junhui of China won the 2013 Indian Open Snooker title with a 5-0 victory over Aditya Mehta of India in New Delhi on 18 October 2013.

Ding Junhui, world number four, 26, scored two century breaks as he earned the 50000 Pounds first prize.

Aditya Mehta, 72nd in the world, became the first Indian player to make the last four of a major ranking event when he reached the semi-finals on 17 October 2013 and he was also first Indian ever to reach the final of the event.

He knocked out former world champions Peter Ebdon and Mark Williams on the way, collecting 25000 pounds as runner-up. The 27-year-old Aditya defeated former world number two Stephen Maguire 4-3 in the semi-final, scoring a highest break of 132.

But he could not match Ding Junhui, who followed a steady run of 52 in the opening frame with breaks of 81, 107, 93 and 100 to clinch victory. Earlier, Ding defeated  England's Robbie Williams 4-1 in his semi-final.

Aditya Mehta fact file

Born: 31 October 1985 in Maharashtra, India

Titles: 2012 Asian champion

Medals: Gold: 2013 World Games (singles), 2009 Asian Indoor Games (team); Silver: 2010 Asian Games (team); Bronze: 2006 Asian Games (team), 2010 Asian Games (singles)

Quick Digest

Where: New Delhi

What: Indian Open Snooker 2013

When: 18 October 2013

Is this article important for exams ? Yes23 People Agreed
Read more Current Affairs on: Ding Junhui , Aditya Mehta

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