MHT CET 2020 Result to be Declared by 28th November, Answer Key to be Out on 10th Nov at mahacet.org

MHT CET 2020 Result Date Announced: As per the latest update, the Maharashtra State CET Cell has formally announced MHT CET 2020 Result Date along with the date for the release of the provisional answer key for the state-level entrance exam. Going by the official notification, the MHT CET 2020 Answer Key will be released on 10th November followed by declaration of MHT CET Result 2020 by 28th November 2020. Like all other important documents and details related to MHT CET 2020, answer keys and results for the entrance test will also be released online on website mahacet.org.

Answer Key to be Out on 10^th November

As per the official announcement, the exam authority i.e. Maharashtra State CET Cell, will release and publish candidates’ response sheets, MHT CET 2020 answer keys and the question papers on 10^th November 2020. All candidates who have appeared for MHT CET 2020 entrance exam seeking admission to BE, BTech, BPharm or DPharm courses, will be able to check their individual response sheets and the provisional answer key for the same on 10^th November 2020. The answer key and response sheets for candidates will be published on official website i.e. mahacet.org.

Challenge Answer Key Until 12^th November

After the publication of MHT CET 2020 Answer Key, the exam authority will open the window to challenge the Maharashtra CET 2020 Provisional Answer Key for all the candidates. The challenge window will remain open for two days only i.e. from 10^th to 12^th November 2020 only. During this window, candidates will be required to raise any challenge or challenge the answers provided in the provisional key. Following the completion of the answer key challenge, MHT CET Result 2020 will be published on 28^th November 2020.

Normalization Formula

The state CET Cell will follow a process of normalization to arrive at the MHT CET 2020 result. MHT CET Percentile Score = 100 x (Number of candidates in exam with normalized marks ≤ the candidate) ÷ Total number of candidates in the exam.