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JEE Advanced Solved Physics Paper-2 Set X

May 12, 2017 19:39 IST

    About the examination

    IIT JEE Examination is held to give admission to various prestigious engineering colleges such as IITs, NITs and various others prestigious engineering institutions.

    This examination is held at two levels: JEE Main and JEE Advanced

    About Paper

    This JEE Advanced Solved Physics Paper-2 in this article consists of 20 questions divided into three sections. The questions in this paper have been asked from the complete syllabus.  Each question of this paper is very important from examination point of view and has been developed very carefully by Subject Experts at Jagranjosh.

    Importance of Practice Papers

    Practicing sample papers, practice papers and previous years’ question papers help in assessing your preparation and time management. It will also help in increasing your marks in examination.

    Some questions from the practice paper are given below:

    Q. Temperature of 1 mole of an ideal gas is increased from 300 K to 310 K under isochoric process. Heat supplied to the gas in this process is Q = 25 R, where R = universal gas constant. What amount of work has to be done by the gas if temperature of the gas decreases from 310 k to 300 K adiabatically.

    (a)    10 R

    (b)    50 R

    (c)    25 R

    (d)   25/2 R

    Correct Option: (c)

    Sol.

    JEE Advanced 2017

    Q. A  tennis  ball  is  dropped  on  a  horizontal  smooth  surface.  It bounces back to its original position after hitting the surface. The force on the ball during the collision is proportional to the length of compression of the ball.  Which one of the following sketches describes the variation of its kinetic energy �� with time �� most appropriately? The figures are only illustrative and not to the scale.

    JEE Advanced 2017

    Sol.

    Correct Option: (b)

    Before collision:

    v = 0 + gt

    v = gt

    So,

    Kinetic Energy = (1/2) m(gt2)

    Therefore, K-t graph before collision is parabola.

    During collision retarding force is just like the spring force i.e. F ∝ x , therefore kinetic energy first decreases to elastic potential energy and then increases. Hence graph (b) is most appropriate.

    Q. The density of a solid ball is to be determined in an experiment. The diameter of the ball is measured with a screw gauge, whose pitch is 0.5 mm and there are 50 divisions on the circular scale.  The reading on the main scale is 2.5 mm and that on the circular scale is 20 divisions.  If the measured mass of the ball has a relative error of 2 %, the relative percentage error in the density is

                     (a) 0.9 %

                     (b) 2.4 %

                     (c) 3.1 %

                     (d) 4.2 %

    Sol.

    Correct option: (c)

    JEE Advanced 2017

    Download Complete Solved Question Paper

    Also get,

    IIT JEE Advanced Question Paper

    IIT JEE Advanced Syllabus

    IIT JEE Advanced Practice Paper

    DISCLAIMER: JPL and its affiliates shall have no liability for any views, thoughts and comments expressed on this article.

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