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SBI PO Exam 2018: Data Interpretation Quiz

Apr 16, 2018 17:26 IST
    SBI PO Exam : DI Quiz
    SBI PO Exam : DI Quiz

    Data Interpretation is one of the most important topics of Quantitative Aptitude section of SBI PO Exam. Aspirants must have clear understanding of the basic concepts of Average, Percentage, Profit and Loss, Ratio and Proportion etc. Solve the below DI quiz and strengthen your preparation for SBI PO exam 2018.

    Direction (Question 1-5) : Study the following information carefully and answer the questions given below:

    The number of students in each of the colleges A, B, C and D is given in the brackets ().

    The vertical axis shows the percentage of students who have opted for Humanities, Commerce and Science respectively.

     


    School A(800)

    School B(600)

    School C(400)

    School D(200)

    Humanities

    35

    40

    32

    42

    Commerce

    36

    32

    24

    18

    Science

    30

    28

    48

    38

     1.   What is the average number of students who have opted for Science from all the schools taken together?

    a)      172

    b)      173

    c)       176

    d)      178

    e)      None of these

    Ans: Option (b)

    Explanation:

    number of students who have opted for Science from all the schools taken together =

    800×30/100 + 600× 28/100 + 400 ×48/100 + 200 ×38/100

    =240+168+192+76

    =692

    Required average =692/4

    =173

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    2.   What is the ratio of the total number of students who have opted for both Science and humanities together from School B to that from School C?

    a)      4 : 5

    b)      5 : 4

    c)       3 : 2

    d)      2  : 3

    e)      None of these

    Ans: Option (b)

    the total number of students who have opted for both Science and humanities together from School B = 600 × 28/100 + 600 ×40/100

    =168+ 240

    = 400

    the total number of students who have opted for both Science and humanities together from School C= 400 ×32/100 + 400 ×48/100

    = 128 +192

    = 320

    required ratio=400/320

    = 5 : 4

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    3.  Which of the following combinations represent the schools with the minimum number of students who have opted for Science and the minimum number of students who have opted for humanities respectively?

    a)      A,C

    b)      A,D

    c)       B, C

    d)      D,B

    e)      None of these

    Ans : Option (e)

    Explanation:

    Number of students opting Science –

    In School A – 800× 30/100 = 240

    In School B  –  66 ×28/100 = 168

    In School C  – 400 ×48/100 = 192

    In School D – 200 ×38/100 = 76

    Hence minimum number of students opting Science is in School D.

    Number of students opting Humanities –

    In School A – 800× 35/100 = 280

    In School B  –  600 × 40/100 = 240

    In School C  – 400 × 32 /100 = 128

    In School D – 200 ×42 /100 = 84

    Hence minimum number of students opting Science is in School D.

    4.  What is the ratio of the number of students who have opted for Humanities from School C to those who have opted for the same subject from School A?

    a)      16 : 35

    b)      12 : 35

    c)       16 : 37

    d)      12 : 37

    e)      None of these

    Ans: Option ( a)

    Explanation:

    number of students who have opted for Humanities from School C =400 ×32/100

    = 128

    number of students who have opted for Humanities from School A =800 ×35/100

    =280

    required ratio = 128/280

    = 16 : 35

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    5.   The number of students who have opted for Science form School A is what per cent of the number of students who have opted for the same subject from School B?

    a)      168

    b)      148

    c)       143

    d)      145

    e)      None of these

    Explanation:

    number of students who have opted for Science form School A = 800 ×30/100

    =240

    number of students who have opted for Science form School B = 600 ×28/100

    = 168

    required percentage= 240 ×100/168

    = 142.85

    ≅ 143

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