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WBJEE 2015 Solved Physics Question Paper – Part 7

Feb 21, 2017 18:00 IST

    Find WBJEE 2015 Solved Physics Question Paper – Part 7 in this article. This paper consists of 5 questions (#31 to #35) from WBJEE 2015 Physics paper. Detailed solution of these questions has been provided so that students can match their solutions.

    Importance of Previous Years’ Paper:

    Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

    About WBJEE Exam

    WBJEE is a common entrance examinations held at state level for admission to the Undergraduate Level Engineering and Medical courses in the State of West Bengal. The Physics section of WBJEE 2015 engineering entrance exam consists of 40 questions.

    31. A cylinder of height h is filled with water and is kept on a block of height h/2. The level of water in the cylinder is kept constant. Four holes numbered 1,2,3 and 4 are at the side of the cylinder and at heights 0, h/4 and 3h/4 respectively. When all four holes are opened together, the hole from which water will reach farthest distance on the plane PQ is the hole no.

    (A) 1

    (B) 2

    (C) 3

    (D) 4

    Ans: (B)

    Sol.

    For maximum range,

    WBJEE 2015

     32. The pressure p, volume v and temperature T for a certain gas are related by

    WBJEE 2015

    where A and B are constants. The work done by the gas when the temperature changes from T1   to T2 while the pressure remains constant, is given by

    WBJEE 2015

    Ans: (C)

    Sol.

    We have,

    WBJEE 2015

    WBJEE 2016 Solved Physics and Chemistry Question Paper

    33. In the circuit shown below, the switch is kept in position ‘a’ for a long time and is then thrown to position ‘b’. The amplitude of the resulting oscillating current is given by

    WBJEE 2015

    Ans: (D)

    Sol.

    The charge through the capacitor is given as:

    qo = CE

    where, C is capacitance and E is potential difference

    Now by conservation of energy,

    Energy stored by capacitor = Energy stored by inductor

    WBJEE 2015

     34. A charge q is placed at one corner of a cube. The electric flux through any of the three faces adjacent to the charge is zero. The flux through any one of the other three faces is

    WBJEE 2015

    Ans: (D)

    Sol.

    Let’s use Gauss's law and symmetry to solve this problem. On placing 7 more identical cubes around the original, the charge is covered symmetrically. So, according to Gauss's law

    WBJEE 2015

    35. Two cells A and B of e.m.f 2V and 1.5V respectively, are connected as shown in figure through an external resistance 10Ω. The internal resistance of each cell is 5 Ω. The potential difference EA and EB across the terminals of the cells A and B respectively are

    WBJEE 2015

    Ans: (C)

    Sol.

    Let i be the current flowing through the circuit

    On applying KVL,

    WBJEE 2015

    WBJEE Sample Question Paper Set-II

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