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CBSE Class 10 Mathematics Exam 2018: Important 1 Mark Questions

Mar 23, 2018 10:21 IST
    CBSE Class 10 Mathematics: Important 1 Mark Questions
    CBSE Class 10 Mathematics: Important 1 Mark Questions

    Here you will get the most important 1 mark questions to prepare for CBSE class 10 Mathematics board exam which will be held on 28 March, 2018. All these questions have been provided with detailed solutions.

    In CBSE Class 10 Mathematics Board Exam 2018, Section - A will comprise 6 questions of 1 mark each.

    Students must practice the important questions given here. This will help them to track their preparedness for the exam and also make them familiarised with the important topics of class 10 Maths. Moreover, the solutions provided here will give students an idea about how to write proper solution to each question in the board exam so as to score optimum marks.

    Given below are some sample questions for CBSE Class 10 Mathematics: Important 1 Mark Questions:

    Q. If the HCF of 65 and 117 is expressible in the form of 65 m – 117, then find the value of m.

    Sol.

    We have, 65 = 13 × 5

    And 117 = 13 × 9

    Hence, HCF = 13

    According to question 65m – 117 = 13

    ⇒  65m = 13 + 117 = 130

    ⇒  m = 130/65 = 2

    Sample Papers with Hints (Issued by CBSE)

    CBSE Class 10 Mathematics Solved Practice Paper 2017-2018: Set-I

    Q. If the common difference of an A.P. is 3, then find a20 – a15.

    Sol.

    Let the first term of the AP be a.

    an = a(n − 1)d

    a20 – a15 = [a + (20 – 1)d] – [a + (15 – 1)d]

                  = 19d – 14d

                  = 5d

                  = 5 × 3

    Q. What is the perimeter of a square circumscribing a circle of radius a cm.

    Sol.

    The radius of the circle is given as a cm.
    Diameter of the circle = 2 × a cm = 2a cm
    Side of the circumscribing square = Diameter of the circle = 2a cm

    ∴ Perimeter of the circumscribing square = 4 × 2a cm = 8a cm

    Q. For what value of k will k + 9, 2 k ‒ 1 and 2k + 7 are the consecutive terms of an A.P.?

    Solution. 

    If three terms x, y and z are in A.P. then, 2 y = x + z

    Since k + 9, 2 k ‒ 1 and 2 k + 7 are in A.P.

    ∴          2(2k − 1) = (k + 9) + (2k + 7)
    ⟹       4k – 2 = 3k + 16

    ⟹       k = 18

     To get the complete set of questions, click on the following link:

    CBSE Class 10 Mathematics: Important 1 Mark Questions

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