NCERT Solutions Class 10 Chapter 13 Maths: NCERT Solutions for Class 10 Maths Chapter 13, "Statistics," help students understand the basics of data collection, organisation, and analysis. This chapter focuses on different methods to represent data, such as graphs, and teaches important concepts like mean, median, and mode. By using these solutions, students can practise a variety of problems and strengthen their grasp of statistical techniques. The solutions also provide step-by-step explanations, making it easier for students to follow and solve the questions. Practising with these solutions helps students build confidence for their exams and improve their problem-solving skills in mathematics.
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NCERT Solutions 10th Maths Chapter 13 Statistics
Get here exercise-wise solutions for Chapter 13 of NCERT Class 10 Maths textbook. Earlier, there used to be four exercises which are now reduced to three.
Exercise 12.1
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find Q1. the mean number of plants per house.
| Number of Plants | 0-2 | 2-4 | 4-6 | 6-8 | 8-10 | 10-12 | 12-14 |
| Number of Houses | 1 | 2 | 1 | 5 | 6 | 2 | 3 |
A survey was conducted by a group of students as a part of their environment awareness programme, in which they collected the following data regarding the number of plants in 20 houses in a locality. Find the mean number of plants per house.
Answer:
To find the mean number of plants per house, we use the assumed mean method because the class intervals are uniform, and this method simplifies the calculation when dealing with large numbers. Here’s the data:
| Number of plants (Class interval) | Number of houses (Frequency, fi) |
|---|---|
| 0 - 2 | 1 |
| 2 - 4 | 2 |
| 4 - 6 | 1 |
| 6 - 8 | 5 |
| 8 - 10 | 6 |
| 10 - 12 | 2 |
| 12 - 14 | 3 |
- First, calculate the class marks (xix_ixi) by taking the midpoints of each class interval.
- Use the formula for the assumed mean method: Mean=A+∑fidi∑fi where A is the assumed mean, fi is the frequency, and di=xi−A is the deviation of the class mark from the assumed mean.
Let me calculate the mean for you.
The mean number of plants per house is 8.1.
The assumed mean method is used here because it simplifies the calculations when dealing with uniform class intervals and larger data sets. By choosing the midpoint of the class intervals as the assumed mean, we reduce the complexity of calculations, especially for finding deviations.
Q2: Consider the following distribution of daily wages of 50 workers of a factory.
| Daily wages (in rupees) | 500-520 | 520-540 | 540-560 | 560-580 | 580-600 |
| Number of workers | 12 | 14 | 8 | 6 | 10 |
Find the mean daily wages of the workers of the factory by using an appropriate method.
Q3. The following distribution shows the daily pocket allowance of children of a locality. The mean pocket allowance is Rs 18. Find the missing frequency f.
| Daily Pocket Allowance (In Rupees) | 11-13 | 13-15 | 15-17 | 17-19 | 19-21 | 21-23 | 23-25 |
| Number of Children | 7 | 6 | 9 | 13 | f | 5 | 4 |
To check the answer to this question and many more, click on the link below and download the complete solution manual.
| Download NCERT Solutions for Class 10 Maths Ch 13 Statistics PDF |
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