NCERT Exemplar Solution for Class 10 Mathematics: Circles (Part-IIB)

CBSE class 10 Mathematics NCERT Exemplar Problems and Solutions for chapter 9- Circles (Part-IIB), is available here. This part constitutes only the Very Short Answer Type Questions. Here you will get solutions to question number 6 to 10 form exercise 9.2 of NCERT Exemplar for Mathematics chapter 9.

Created On: Aug 8, 2017 12:30 IST

Here you get the CBSE Class 10 Mathematics chapter 9, Circles: NCERT Exemplar Problems and Solutions (Part-IIB). In this part you will get solutions to Question Number 6 to 10 from exercise 9.2 of NCERT Exemplar Problems for Class 10 Mathematics Chapter: Circles. Each solution is designed to give you an apt explanation and that too in simple steps. For solutions to Question Number 1 to 5 of exercise 9.2, check the following link:

NCERT Exemplar Solution for Class 10 Mathematics: Circles (Part-IIA)

NCERT exemplar problems are a very good resource for preparing the critical questions like Higher Order Thinking Skill (HOTS) questions. All these questions are very important to prepare for CBSE Class 10 Mathematics Board Examination 2017-2018 as well as other competitive exams.

Find below the NCERT Exemplar problems and their solutions for Class 10 Mathematics Chapter, Circles:

Exercise 9.2

Very Short Answer Type Questions (Q. No. 6-10)

Question. 7 The tangent to the circumcircle of an isosceles ΔABC at A, in which AB = AC, is parallel to BC.

Solution.   True

Let DE be the tangent to the circumcircle of an isosceles ΔABC at A.

Question. 8 If a number of circles touch a given line segment PQ at a point A, then their centres lie on the perpendicular bisector of PQ.

Solution. False

Let circles S1, S2, S3, S4, ... with centres C1, C2, C3, C4, ..., respectively, touch the line segment PQ at a point A.

We know that perpendicular on any point of a segment PQ may be only one. Therefore, all the line segments C1A, C2A. C3A,..., so on are coincident.

But as A is not mid point of PQ therefore, perpendicular AB will not be the perpendicular bisector of PQ.

Thus, the centre of each circle lies on a line segment which is perpendicular to PQ but not its bisector.

Question. 9 If a number of circles pass through the end points P and Q of a line segment PQ, then their centres lie

on the perpendicular bisector of PQ.

Solution. True

Let S1, S2 and S3  be the circles with centres C1, C2 and C3, respectively, passing through the end points P and Q of a line segment PQ.

As we know that the perpendicular bisectors of a chord of a circle always passes through the centre of circle.

Thus, perpendicular bisector of PQ passes through C1, C2 and C3. Similarly, all the circle passing through PQ will have their centre on perpendiculars bisectors of PQ.

Question. 10 AB is a diameter of a circle and AC is its chord such that Ð BAC = 30°. If the tangent at C intersects A extended at D, then BC = BD.

Solution. True

Consider the following diagram:

NCERT Solutions for CBSE Class 10 Maths

NCERT Exemplar Problems and Solutions Class 10 Science: All Chapters

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