1. Home
    2. |  
  2. CBSE Board |  

NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Part V)

Jul 5, 2017 12:05 IST

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Part V)

    NCERT Solutions for CBSE Class 12th Mathematics, Chapter 2: Inverse Trigonometric Functions are available here. Here, you will get solutions of exercise 2.2 (from question number 11 to question number 15). The questions given in this exercise are based on basic properties of inverse trigonometric functions. These questions are important for CBSE Class 12 board exam 2018.

    NCERT Solutions for CBSE Class 12th Maths, Chapter 2: Inverse Trigonometric Functions (Exercise 2.2) are given below

    Question 11:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Question 11

    Solution 11:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Solution 11

    Therefore, the value of expression is π/4.

    CBSE Class 12 Maths Syllabus 2017 - 2018

    Question 12:

    cot (tan‒1a + cot‒1a)

    Solution 12:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Solution 12

    Therefore, cot (tan‒1a + cot‒1a) = 0

    Question 13:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Question 13

    Solution 13:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Solution 13

    Question 14:

    If sin {sin‒1(1/5) + cos‒1(x)} =1, then find the value of x

    Solution 14:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Solution 14

    The value of x = 1/5.

    Question 15:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Question15

    Solution 15:

    NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Exercise 2.2), Solution 15

    Therefore, the value of x = π/3.

    Download NCERT Solutions for Class 12 Mathematics Chapter 2 - Inverse Trigonometric Functions in PDF Format
    Previous Story NCERT Solutions for CBSE Class 12 Mathematics ‒ Chapter 2: Inverse Trigonometric Functions (Part VI)
    Next Story NCERT Exemplar Solution for CBSE Class 10 Mathematics: Arithmetic Progressions (Part-II)
    Library

    Register to get FREE updates

      All Fields Mandatory
    • (Ex:9123456789)
    • Please Select Your Interest

    • Please specify

    • ajax-loader

    • A verifcation code has been sent to
      your mobile number

      Please enter the verification code below

    Jagran Prakashan Ltd @ 2018
    This website uses cookie or similar technologies, to enhance your browsing experience and provide personalised recommendations. By continuing to use our website, you agree to our Privacy Policy and Cookie Policy. OK
    X

    Register to view Complete PDF