# NCERT Solutions for Class 7 Mathematics: Chapter - 6 The Triangle and its Properties

Check NCERT Solutions for Class 7 Mathematics (Chapter - 6 The Triangle and its Properties). With this article, you will get solutions to all the questions of Class 7 Maths NCERT Textbook, Chapter - 6 The Triangle and its Properties.

*NCERT Solutions: Class 7 Maths - Chapter 6*

Check NCERT Solutions for Class 7 Mathematics, Chapter - 6 The Triangle and its Properties. This chapter is one of the most important chapters of CBSE Class 7 Mathematics subject. Students of Class 7 are advised to prepare this chapter well, as concepts given in this chapter are required to solve questions of other chapters.

**NCERT Solutions for Class 7 Mathematics, Chapter - 6 The Triangle and its Properties**

**1. **In Δ PQR, D is the mid-point of QR.

(i) PM is _________________.

(ii) PD is _________________.

(iii) Is QM = MR?

Solutions:

(i) Altitude

(ii) Median

(iii) No

**2. **Draw rough sketches for the following:

(a) In ΔABC, BE is a median.

(b) In ΔPQR, PQ and PR are altitudes of the triangle.

(c) In ΔXYZ, YL is an altitude in the exterior of the triangle.

**Solutions:**

**(a)**

**(b)**

**(c)**

**3. **Verify by drawing a diagram if the median and altitude of an isosceles triangle can be same.

**Solution:**

After drawing isosceles triangle ABC and drawing altitude AD, we observed that BD = DC. So AD is also a median.

**EXERCISE 6.2**

1. Find the value of the unknown exterior angle x in the following diagrams:

Solutions:

(i) Using exterior angle theorem, we have, *x* = 50° + 70° ⇒ *x* = 120°

(ii) Using exterior angle theorem, we have, *x* = 65° + 45° ⇒ *x *= 110°

(iii) Using exterior angle theorem, we have, *x* = 40° + 30° ⇒ *x *= 70°

(iv) Using exterior angle theorem, we have, *x* = 60° + 60°⇒ *x *= 120°

(v) Using exterior angle theorem, we have, *x* = 50° + 50° ⇒ *x *= 100°

(vi) Using exterior angle theorem, we have *x* = 30° + 60° ⇒ *x *= 90°

Solutions of rest of the questions will be available here shortly.

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