SSC conducts several exams for recruiting candidates for various banks. SSC MTS exam is among them. To crack SSC MTS exam, a candidate has to work very hard seriously and cover all the questions of each topic.

In this article, we have prepared a set of 10 questions hailed from number system with answers. As there is no specific syllabus of any banking exam. Yet, we have managed to gather the topics through a detailed analysis of previous year paper. The difficulty level of questions is very easy. Therefore, practice all questions attentively-

**SSC MTS study material: Number system**

**1. Express 0.2797979.. in the form of a fraction?**

a. 279/990

b. 289/990

c. 277/990

d. 297/999**Ans.: - (c.)Explanation: -** Let x= 0.2797979…

10x= 2 + 0.797979….; --------eq.(1)

Let y = 0.797979..; => 100y = 79 + 0.797979…;

100y = 79 + y; => y= 79/99;

Use value of y in eq.(1);

10x= 2 + (79/99); => x= 277/990;

**2. Find the number of factors 1120 excluding 1 and itself?**

a. 20

b. 22

c. 24

d. 26**Ans.:- (b.)Explanation: -** After factorization, we get-

1120 = 25 * 5 * 7;

Hence, the total number of factors= (5 +1) * (1 + 1) * (1 + 1) = 24.

This number includes 1 and 1120 itself as a factor. Excluding them, we will get = 24-2=22.

**3. Find the smallest number which when divided by 7 and 8 leaves a remainder of 3 in each case?**

a. 57

b. 58

c. 59

d. 61**Ans.:- (c.)Explanation:- **Find LCM of both divisors;

LCM (7, 8) = 56;

Since, dividend leaves 3 remainder in each case; hence the number will be = 56 + 3= 59.

**4. If the sum of five consecutive numbers is k, then the second largest of those integers in terms of S will be**

a. (S – 10)/5

b. ( S + 5 )/ 5

c. (S + 4)/ 4

d. None of these**Ans.:- (b.)Explanation: -** let the first number is n; then-

n + (n +1) + (n + 2) + (n + 3) + (n + 4) = S;

5n + 10 = S; => n= (S – 10)/5;

Hence, the second largest in the series will be = n + 3 = (S – 10)/5 + 3= (S + 5)/ 5.

**5. In a division, the divisor is 3 times the quotient and 3 times the remainder. If the remainder is 14, then the dividend is**

a. 502

b. 598

c. 602

d. 614**Ans.:- (c.)Explanation: -** As per the conditions stated in question-

Divisor = 3 * Remainder;

Divisor = 3*14 = 42;

Divisor = 3 * quotient; => quotient= 42/3= 14;

Dividend = Divisor * Quotient + Remainder;

Dividend= 42 * 14 + 14 = 602.

**6. Find out the wrong term in the following sequence7, 28, 63, 124, 215, 342, 511**

a. 28

b. 63

c. 215

d. 511

**Ans.:- (a.)**

Explanation: -

Explanation: -

7 = 23 – 1;

28 != 33 – 1;

63 = 43 – 1;

124 = 53 – 1;

215 = 63 – 1;

342 = 73 – 1;

511 = 83 – 1;

**7. The sum of two numbers is 9 and their product is 18. Find the sum of the reciprocals of both numbers?**

a. ¼

b. ½

c. 1/3

d. 1/5**Ans.:- (b.)Explanation: - **let first and second numbers are a and b respectively;

a + b = 9; ------eq. (1)

a * b = 18; ------- eq. (2)

(a – b)2 = (a + b)2 – 4* ab;

Put the values from eq. (1) and eq. (2)-

=> (a – b)2= 92 – 4 * 18;

a – b = 3; ------eq. (3)

from eq. (1) and eq. (3), the value of a & b;

a = 6 and b= 3;

hence, the sum of the reciprocals (1/a + 1/b) = (1/6 + 1/3) =1/2.

**8. If x * y = (x – 3)3 * (y – 2), then find the value of 5 * 7?**

a. 30

b. 35

c. 38

d. 40**Ans.- (d.)Explanation: -** Put x=5 and y=7 in the given expression,

5 * 7 = (5 – 3)3 * (7 – 2);

= 23 * 5 = 40

**9. If 262*7 is divisible by 11, then find the number, which will take place of *?**

a. 3

b. 4

c. 5

d. 6**Ans.:- (c.)Explanation:-**A number is only divisible by 11 if the difference between the digits of odd places and even places is divisible by 11.

Hence, difference= (2 + 2 + 7) – (6 + *)

= 11 – 6 - *

= 5 - *

This will be divisible by 11 only if it became zero. Hence, the value of * will be 5.

**10. The value of 1 + 2 + 3 + ……. + 25 + 24 + 23 + 22 +…….+ 3 + 2 + 1 is**

a. 600

b. 615

c. 620

d. 625**Ans.:-(d.)Explanation: -**

1 + 2 + 3 + ……. + 25 + 24 + 23 + 22 +…….+ 3 + 2 + 1 = 2 * (1 + 2 + 3 + ……. + 25) – 25;

= 2 * (25* 26)/2 -25;

= 25 * 25 = 625.

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**All The Best!!**

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