 SSC MTS exam study material: Number system-I

In this article, we have prepared a set of 10 questions hailed from number system with answers. practice all questions attentively- SSC MTS number system

SSC conducts several exams for recruiting candidates for various banks. SSC MTS exam is among them. To crack SSC MTS exam, a candidate has to work very hard seriously and cover all the questions of each topic. In this article, we have prepared a set of 10 questions hailed from number system with answers. As there is no specific syllabus of any banking exam. Yet, we have managed to gather the topics through a detailed analysis of previous year paper. The difficulty level of questions is very easy. Therefore, practice all questions attentively-

SSC MTS study material: Number system

1. Express 0.2797979.. in the form of a fraction?
a. 279/990
b. 289/990
c. 277/990
d. 297/999
Ans.: - (c.)
Explanation: -
Let x= 0.2797979…
10x= 2 + 0.797979….; --------eq.(1)
Let y = 0.797979..; => 100y = 79 + 0.797979…;
100y = 79 + y; => y= 79/99;
Use value of y in eq.(1);
10x= 2 + (79/99); => x= 277/990;

2. Find the number of factors 1120 excluding 1 and itself?
a. 20
b. 22
c. 24
d. 26
Ans.:- (b.)
Explanation: -
After factorization, we get-
1120 = 25 * 5 * 7;
Hence, the total number of factors= (5 +1) * (1 + 1) * (1 + 1) = 24.
This number includes 1 and 1120 itself as a factor. Excluding them, we will get = 24-2=22.

3. Find the smallest number which when divided by 7 and 8 leaves a remainder of 3 in each case?
a. 57
b. 58
c. 59
d. 61
Ans.:- (c.)
Explanation:-
Find LCM of both divisors;
LCM (7, 8) = 56;
Since, dividend leaves 3 remainder in each case; hence the number will be = 56 + 3= 59.

4. If the sum of five consecutive numbers is k, then the second largest of those integers in terms of S will be
a. (S – 10)/5
b. ( S + 5 )/ 5
c. (S + 4)/ 4
d. None of these
Ans.:-  (b.)
Explanation: -
let the first number is n; then-
n + (n +1) + (n + 2) + (n + 3) + (n + 4) = S;
5n + 10 = S; => n= (S – 10)/5;
Hence, the second largest in the series will be = n + 3 = (S – 10)/5 + 3= (S + 5)/ 5.

5. In a division, the divisor is 3 times the quotient and 3 times the remainder. If the remainder is 14, then the dividend is
a. 502
b. 598
c. 602
d. 614
Ans.:- (c.)
Explanation: -
As per the conditions stated in question-
Divisor = 3 * Remainder;
Divisor = 3*14 = 42;
Divisor = 3 * quotient; => quotient= 42/3= 14;
Dividend = Divisor * Quotient + Remainder;
Dividend= 42 * 14 + 14 = 602.

6. Find out the wrong term in the following sequence
7, 28, 63, 124, 215, 342, 511

a. 28
b. 63
c. 215
d. 511
Ans.:- (a.)
Explanation: -

7 = 23 – 1;
28 != 33 – 1;
63 = 43 – 1;
124 = 53 – 1;
215 = 63 – 1;
342 = 73 – 1;
511 = 83 – 1;

7. The sum of two numbers is 9 and their product is 18. Find the sum of the reciprocals of both numbers?
a. ¼
b. ½
c. 1/3
d. 1/5
Ans.:- (b.)
Explanation: -
let first and second numbers are a and b respectively;
a + b = 9; ------eq. (1)
a * b = 18; ------- eq. (2)
(a – b)2 = (a + b)2 – 4* ab;
Put the values from eq. (1) and eq. (2)-
=> (a – b)2= 92 – 4 * 18;
a – b = 3; ------eq. (3)
from eq. (1) and eq. (3), the value of a & b;
a = 6 and b= 3;
hence, the sum of the reciprocals (1/a + 1/b) = (1/6 + 1/3) =1/2.

8. If x * y = (x – 3)3 * (y – 2), then find the value of 5 * 7?
a. 30
b. 35
c. 38
d. 40
Ans.- (d.)
Explanation: -
Put x=5 and y=7 in the given expression,
5 * 7 = (5 – 3)3 * (7 – 2);
= 23 * 5 = 40

9. If 262*7 is divisible by 11, then find the number, which will take place of *?
a. 3
b. 4
c. 5
d. 6
Ans.:- (c.)
Explanation:-
A number is only divisible by 11 if the difference between the digits of odd places and even places is divisible by 11.
Hence, difference= (2 + 2 + 7) – (6 + *)
= 11 – 6 - *
= 5 - *
This will be divisible by 11 only if it became zero. Hence, the value of * will be 5.

10. The value of 1 + 2 + 3 + ……. + 25 + 24 + 23 + 22 +…….+ 3 + 2 + 1 is
a. 600
b. 615
c. 620
d. 625
Ans.:-(d.)
Explanation: -

1 + 2 + 3 + ……. + 25 + 24 + 23 + 22 +…….+ 3 + 2 + 1 = 2 * (1 + 2 + 3 + ……. + 25) – 25;
= 2 * (25* 26)/2 -25;
= 25 * 25 = 625.
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