UPSEE is a state level entrance examination for various disciplines. Many prestigious government and private college is associated with this university.
In this regard, find UPSEE 2017 Solved Chemistry Sample Paper Set-III. Solving sample papers and previous year question papers are must do activities to do good in any entrance examination. Questions in this paper are prepared with great expertise and every question of this paper is important for UPSEE 2017 Examination.
This paper consists of 50 questions. Four marks will be awarded for each correct answer and zero mark will be awarded for incorrect/unattempted questions. Questions given in this paper cover complete syllabus of UPSEE. All questions are very important as they are developed with great expertise.
Few questions from the sample paper are given below:
Q. Silver iodide is used for producing artificial rains because silver iodide
(A) is easy to spray at high altitude
(B) is insoluble in water
(C) has crystal structure similar to ice
(D) is easy to synthesize
Correct Option: (C)
Sol. Silver iodide is used for producing artificial rains because it has crystal structure similar to ice. When AgI is sprayed over clouds it causes water droplets of clouds to coalesce to form bigger water drops and induce rains.
Q. What conclusions can be drawn from the following reactions?
H2 + 4.5 eV → H + H
H + 13.6 eV → H+ + e-
(A) It is more difficult to break up an H2 molecule than it is to ionize a hydrogen atom.
(B) It is easier to break up an H2 molecule than it is to ionize a hydrogen atom.
(C) The average energy of formation of H and H+ are the same.
(D) Electron and proton attraction in an H2 molecule as well as in H atoms are the same.
Correct Option: (B)
Sol. Required amount of energy for formation of H+ ion from H atom is greater than that for formation of Hydrogen atom from H2 molecules.
Q. 1.00 × 10-3 mol of Ag+ and 1.00 × 10-3 mol of CrO42− react together to form solid Ag2CrO4. Calculate the amount of Ag2CrO4 formed
(MgAg2CrO4 = 331.73g mol-1)
(A) 0.268 g
(B) 0.166 g
(C) 0.212 g
(D) 1.66 g
Correct Option: (B)
Sol. 2 Ag+ + CrO42- → Ag2CrO4
Given mole 1 × 10-3
Hence Ag+ will be limiting reagent.
Moles of Ag2CrO4 formed = 0.5 × 10-3
Mass of Ag2CrO4 formed = 0.5 × 10-3 × 331.73g= 0.166 g