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WBJEE 2014 Solved Mathematics Question Paper – Part 15

Apr 24, 2017 18:40 IST

    Find WBJEE 2014 Solved Mathematics Question Paper – Part 15 in this article. This paper consists of 5 questions (#71 to #75  ) from WBJEE 2014 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.

    About WBJEE Exam

    WBJEE is a common entrance examinations held at state level for admission to the undergraduate level engineering and medical courses in the state of West Bengal. The Mathematics section of WBJEE 2014 engineering entrance exam consists of 80 questions.

    Importance of Previous Years’ Paper:

    Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

    WBJEE 2014

    (A) is equal to zero

    (B) lies between 0 and 3

    (C) is a negative number

    (D) lies between 3 and 6

    Ans: (C)

    Sol:

    WBJEE 2014

    Clearly it is a negative number.

    72. A student answers a multiple choice question with 5 alternatives, of which exactly one is correct. The probability that he knows the correct answer is p, 0 < p < 1. If he does not know the correct answer, he randomly ticks one answer. Given that he has answered the question correctly, the probability that he did not tick the answer randomly, is

    WBJEE 2014

    Ans: (c)

    Sol:

    Let us suppose that,

    The probability that the student knows the answer = Y

    The probability that the student do not know the answer = N

    The probability that student choose correct option = C

    WBJEE 2014

    73. A poker hand consists of 5 cards drawn at random from a well-shuffled pack of 52 cards. Then the probability that a poker hand consists of a pair and a triple of equal face values (for example 2 sevens and 3 kings or 2 aces and 3 queens, etc.) is
    (A) 6/4165
    (B) 23/4165
    (C) 1797/4165
    (D) 1/4165

    Ans: (A)
    Sol:


    Total number of combination of 5 cards out of 52 cards = C(52, 5)
    Consider 4 cards of the same face value,
    Total number of combination of 2 cards out of 4 cards = C(4, 2)
    Total number of combination of 2 cards out of 4 cards = C(4, 3)
    Considering two sets of 4 cards with equal face values, the possible combination is
    C(4, 2). C(4, 3)
    There are 13 sets of so, total combination = C(13, 2)⋅C(4, 2)⋅C(4, 3)
    Now, for each pair of ranks, we can have a pair of cards from the first rank and a triple from the second rank, or a triple from the first rank, and a pair from the second rank. So, we should multiply by 2.
    So, the probability that a poker hand consist of a pair and a triple of equal face values is

    WBJEE 2014

    WBJEE 2014

    (A) 0

    (B) 51/2

    (C) 21/2

    (D) 1

    Ans : (C)

    Sol.

    WBJEE 2014

    WBJEE 2014

    WBJEE 2014

    WBJEE 2014

    Also Get:

    WBJEE Sample Papers

    WBJEE Previous Years' Question Papers

    WBJEE Online Test

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