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WBJEE 2014 Solved Mathematics Question Paper – Part 9

This article contains 5 questions (#41 to #45) from WBJEE 2014 Solved Mathematics Question Paper. This solved paper will help students in their final level of preparation for WBJEE Engineering Exam.

Mar 27, 2017 18:15 IST
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Find WBJEE 2015 Solved Mathematics Question Paper – Part 9 in this article. This paper consists of 5 questions (#41 to #45) from WBJEE 2014 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.

Importance of Previous Years’ Paper:

Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

About WBJEE Exam

WBJEE is a common entrance examinations held at state level for admission to the undergraduate level engineering and medical courses in the state of West Bengal. The Mathematics section of WBJEE 2014 engineering entrance exam consists of 80 questions.

WBJEE 2014

(A) 1

(B) –1

(C) 2

(D) loge2

Ans: (A)

Sol:

WBJEE 2014

WBJEE 2014

Ans: (C)

Sol.

WBJEE 2014

43. There is a group of 265 persons who like either singing or dancing or painting. In this group 200 like singing, 110 like dancing and 55 like painting. If 60 persons like both singing and dancing, 30 like both singing and painting and 10 like all three activities, then the number of persons who like only dancing and painting is

(A) 10

(B) 20

(C) 30

(D) 40

Ans: (A)  

Sol:

Let the number of people who like singing be S, who like painting be P and who like dancing be D.

n(S ∪ P ∪ D) = 265

n(S) = 200

n(D) = 110

n(P) = 55

n(S ∩ D) = 60

n(S ∩ P) = 30

n(S ∩ D ∩ P) = 10

n(S ∪ P ∪ D) = n(S) + n(D) + n(P) – n(S ∩ D) – n(D ∩ P) – n(P ∩ S) + n(S ∩ D ∩ P)

265 = 200 + 110 + 55 – 60 – 30 – n(P ∩ D) + 10

n(P ∩ D) = 285 – 265 = 20

n(P ∩ D) – n(P ∩ D ∩ S) = 20 – 10 = 10

WBJEE 2014

Ans: (A)

Sol:

WBJEE 2014

45. Suppose that z1, z2, z3 are three vertices of an equilateral triangle in the Argand plane. Let

α = 1/2(√3 + i) and β be a non-zero complex number. The points αz1 + β, αz2 + β, αz3 + β will be

(A) The vertices of an equilateral triangle

(B) The vertices of an isosceles triangle

(C) Collinear

(D) The vertices of an scalene triangle

Ans : (A)

Sol.

Since, z1, z2, z3 are three vertices of an equilateral triangle, so

WBJEE 2014

Also Get:

WBJEE Sample Papers

WBJEE Previous Years' Question Papers

WBJEE Online Test

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