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WBJEE 2015 Solved Mathematics Question Paper – Part 7

Feb 8, 2017 18:16 IST

    Find WBJEE 2015 Solved Mathematics Question Paper – Part 7 in this article. This paper consists of 10 questions (#61 to #70) from WBJEE 2015 Mathematics paper. Detailed solution of these questions has been provided so that students can match their solutions.

    Importance of Previous Years’ Paper:

    Previous years’ question papers help aspirants in understanding exam pattern, question format, important topics and assessing preparation. It has also been seen that sometimes questions are repeated in WBJEE Exam. So, this paper will certainly boost your confidence.

    About WBJEE Exam

    WBJEE is a common entrance examinations held at state level for admission to the Undergraduate Level Engineering and Medical courses in the State of West Bengal. The WBJEE engineering entrance exam has two sections – Mathematics, Physics and Chemistry. The Mathematics section of WBJEE 2015 engineering entrance exam consists of 80 questions.

    IIT JEE, IIT JEE Sample Paper

    (A) b + c

    (B) c + a

    (C) a + b

    (D) a + b + c

    Correct Option: (C)

    Sol.

    IIT JEE, IIT JEE Sample Paper

    In the above figure, OECD is a square since all angles are right angle.

    So,

    BE = a – r

    And, AD = b – r

    Also, tangents drawn from an external point are equal.

    So,

    BF = BE

    And, AF = AD

    IIT JEE, IIT JEE Sample Paper

    IIT JEE, IIT JEE Sample Paper

    (A) a + b = c

    (B) b + c = a

    (C) c + a = b

    (D) c = a

    Correct Option: (D)

    Sol.

    We know that,

    IIT JEE, IIT JEE Sample Paper

    Now putting above values in the given equation,

    IIT JEE, IIT JEE Sample Paper

    IIT JEE, IIT JEE Sample Paper

    Then sum of the elements of U–1 is

    (A) 6

    (B) 0

    (C) 1

    (D) 2/3

    Correct Option: (B)

    Sol.

    IIT JEE, IIT JEE Sample Paper

    IIT JEE, IIT JEE Sample Paper

    WBJEE 2016 Solved Physics and Chemistry Question Paper

    IIT JEE

    (A) 1000

    (B) 500

    (C) 1/500

    (D) 1/1000

    Correct Option: (D)

    Sol.

    IIT JEE

    65. If 5 distinct balls are placed at random into 5 cells, then the probability that exactly one cell remains empty is

    (A) 48/125

    (B) 12/125

    (C) 8/125

    (D) 1/125

    Correct Option: (A)

    Sol.

    If we have to keep exactly one cell empty, then one of the cell must contain 2 balls and the remaining cell must contain one ball each.

    IIT JEE

    Now let us assume two balls as one unit.

    So, we have now 4 units to be arranged in 4 places.

    This can be done in 4! ways.

    IIT JEE

    66. A survey of people in a given region showed that 20% were smokers. The probability of death due to lung cancer, given that a person smoked, was 10 times the probability of death due to lung cancer, given that a person did not smoke. If the probability of death due to lung cancer in the region is 0.006, what is the probability of death due to lung cancer given that a person is a smoker?

    (A) 1/140

    (B) 1/70

    (C) 3/140

    (D) 1/10

    Correct Option: (C)

    Sol.

    IIT JEE

    Let us assume that,

    S = person is smoker

    NS = person is non smoker

    D = death due to lung cancer

    IIT JEE

    67. A person goes to office by a car or scooter or bus or train, probability of which are 1/7, 3/7, 2/7 and 1/7 respectively. Probability that he reaches office late, if he takes car, scooter, bus or train is 2/9, 1/9, 4/9, and 1/9 respectively.

    Given that he reached office in time, the probability that he travelled by a car is

    (A) 1/7

    (B) 2/7

    (C) 3/7

    (D) 4/7

    Correct Option : (A)

    Sol.

    IIT JEE

    IIT JEE

    IIT JEE

    IIT JEE

    WBJEE Sample Question Paper Set-II

    IIT JEE

    (A) 2015

    (B) 0

    (C) 2015 × 2016

    (D) 2015 × 2014

    Correct Option: (C)

    Sol.

     Applying L’ Hospital Rule,

    IIT JEE

    70. If x and y are digits such that 17! = 3556xy428096000, then x + y equals

    (A) 15

    (B) 6

    (C) 12

    (D) 13

    Correct Option : (A)

    Sol.

    Since 17! is divisible by all numbers less than or equal to 17.

    So, 17! is also be divisible by 9.

    So,

    3+5+5+6+x+y+4+2+8+0+9+6+0+0+0 is divisible by 9

    48 + x + y must be divisible by 9.

    So, x + y can be 15 or 6.

    WBJEE 2016 Solved Mathematics Question Paper

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