# CBSE Class 10 Mathematics Exam 2018: Important 2 Marks Questions

Mar 23, 2018 10:02 IST
CBSE Class 10 Mathematics: Important 2 Marks Questions

CBSE Class 10 Mathematics board exam paper is shecduled to be held on 28 March, 2018. To help students prepare in the last days before the exam, we are providing here a collection of important 2 marks questions which may be asked in the class 10 Mathematics board paper. All these questions have been prepared by analysing the concepts and topics based on which questions were asked in the previous years’ board exams. Each question has been provided with a proper solution.

In CBSE Class 10 Mathematics Board Exam 2018, Section - B will comprise 6 questions of 2 marks each.

Students must practice these important questions to acquaint with the important topics of class 10 Maths and track their preparedness for the board exam 2018. Moreover, the solutions provided here will give students an idea about how to write proper solutions to each question in the board exam so as to score optimum marks.

Given below are some sample questions for CBSE Class 10 Mathematics: Important 2 Marks Questions:

Q.  Find the number of all three-digit natural numbers which are divisible by 9.

Solution.

All three-digit natural numbers which are divisible by 9, are 108, 117, 126, ….., 999.

All these numbers form an AP with, 1st term, a =108

Common difference, d =117 – 108 = 9

And last term, an = 999
Now, a + (n − 1) d = an
&there4;108 + (n − 1) 9 = 999
⟹ (n − 1)9 = 999 −108 = 891

⟹ (n − 1) = 891 /9 = 99

⟹ n = 99 + 1 = 100

Q. Solve the following system of linear equations by substitution method:

2x y = 2

x + 3y =15

Sol.

Here,   2x y = 2

⟹       y = 2x – 2

⟹       x + 3y = 15

Substituting the value of y from (i) in (ii), we get

x + 6x – 6 = 15

⟹       7x = 21

⟹         x = 3

From (i), y = 2 × 3 – 2 = 4

&there4;             x = 3 and y = 4

CBSE Class 10 Mathematics Exam 2018: Important 1 Mark Questions

Q. A card is drawn at random from a pack of 52 playing cards. Find the probability that the card drawn is neither an ace nor a king.

Sol.

P (neither an ace nor a king)

= 1 – P(either an ace or a king)

= 1 – [P(an ace) + P (a king)]

= 1 – [4/52  +  4/52]

= 1 – 8/52

= 44/52  =  11/13

To get the complete set of questions, click on the following link:

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