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CBSE Class 9 Mathematics Solved Practice Paper : Set-I

Nov 30, 2017 17:27 IST
    CBSE Class 9 Mathematics Solved Practice Paper
    CBSE Class 9 Mathematics Solved Practice Paper

    Here we bring you the CBSE Class 9 Mathematics Solved Practice Paper : Set-I. This practice paper has been designed as per the latest exam structure and coveres the whole syllabus of Class 9 Maths. It will help you get acquainted with the important topics to be prepared for the Class 9th Mathematics Annual Exam 2018.

    CBSE Class 9 Exam Pattern 2017-2018

    NCERT Solutions for CBSE Class 9 Maths

    With a thorough analysis of the CBSE’s criteria to set papers for finals, subject experts at jagranjosh has designed the CBSE Class 9 Mathematics Solved Practice Paper : Set-I that will make you familiar with important questions that will ultimately help you prepare better for the new assessment structure, i.e., periodic tests as well as the annual exams 2017-2018.

    Some of the sample questions from CBSE Class 9 Mathematics Solved Practice Paper : Set-I are given below:

    Q. Find the radius of largest sphere that is carved out of the cube of side 8 cm.

    Sol.

    The largest sphere can be carved out from a cube, if we take diameter of the sphere equal to edge of the cube.
    Diameter of the sphere = 8 cm
    Thus, radius of the sphere = 8/2 = 4cm

    Q. An angle is 14o more than its complement. Find its measure.

    Sol.

    Let the measure of the angle be x.

    Now, two complementary angles have sum equal to 90o.

    So, measure of its complement = 90 − x

    From the given condition, we have:

                x = 14 + (90 − x)

    ⟹       2x = 104

    ⟹       x = 52o

    Q. Without actual division, prove that (2x4 − 6x3 + 3x2 + 3x – 2) is exactly divisible by (x2 − 3x +2).

    Sol.

    Let  f(x) = 2x4– 6x3 + 3x2 + 3x – 2      

    And g(x) =  x2– 3+ 2  

                   = x2– 2x+ 2   

                   = x (x – 2) −1(x – 2) = (x – 1) (x – 2)

    Now  if  x2– 3+ 2  is a factor of  f(x)

    Then  (x – 1)  and  (x – 2)  both should be factors of  f(x)

    Then,  (1)  =  (2)  =  0

    So,  f(1)  =  2.14– 6.13 + 3.12 + 3.1 – 2 

    =  2 – 6 + 3 + 3 – 2 = 0

    f(2) =   2.24– 6.23 + 3.22 + 3.2 – 2

    =  32 – 48 + 12 + 6 – 2 = 0

    Since  f(1) = f(2) = 0

    f(x) = 2x4– 6x3 + 3x2 + 3x – 2 is exactly divisible by (x – 1)  and  (x – 2).

    ∴  x2 – 3+ 2  is a factor of  f(x).

    Get the complete practice paper by clicking on the following link:

    CBSE Class 9 Mathematics Solved Practice Paper : Set-I

    Here we bring you the CBSE Class 9 Mathematics Solved Practice Paper : Set-I. This practice paper has been designed as per the latest exam structure and coveres the whole syllabus of Class 9 Maths. It will help you get acquainted with the important topics to be prepared for the Class 9th Mathematics Annual Exam 2018.

    CBSE Class 9 Exam Pattern 2017-2018

    NCERT Solutions for CBSE Class 9 Maths

    With a thorough analysis of the CBSE’s criteria to set papers for finals, subject experts at jagranjosh has designed the CBSE Class 9 Mathematics Solved Practice Paper : Set-I that will make you familiar with important questions that will ultimately help you prepare better for the new assessment structure, i.e., periodic tests as well as the annual exams 2017-2018.

    Some of the sample questions from CBSE Class 9 Mathematics Solved Practice Paper : Set-I are given below:

    Q. Find the radius of largest sphere that is carved out of the cube of side 8 cm.

    Sol.

    The largest sphere can be carved out from a cube, if we take diameter of the sphere equal to edge of the cube.
    Diameter of the sphere = 8 cm
    Thus, radius of the sphere = 8/2 = 4cm

    Q. An angle is 14o more than its complement. Find its measure.

    Sol.

    Let the measure of the angle be x.

    Now, two complementary angles have sum equal to 90o.

    So, measure of its complement = 90 − x

    From the given condition, we have:

                x = 14 + (90 − x)

           2x = 104

           x = 52o

    Q. Without actual division, prove that (2x4 − 6x3 + 3x2 + 3x – 2) is exactly divisible by (x2 − 3x +2).

    Sol.

    Let  f(x) = 2x4– 6x3 + 3x2 + 3x – 2      

    And g(x) =  x2– 3+ 2  

                   = x2– 2x+ 2   

                   = x (x – 2) −1(x – 2) = (x – 1) (x – 2)

    Now  if  x2– 3+ 2  is a factor of  f(x)

    Then  (x – 1)  and  (x – 2)  both should be factors of  f(x)

    Then,  (1)  =  (2)  =  0

    So,  f(1)  =  2.14– 6.13 + 3.12 + 3.1 – 2 

    =  2 – 6 + 3 + 3 – 2 = 0

    f(2) =   2.24– 6.23 + 3.22 + 3.2 – 2

    =  32 – 48 + 12 + 6 – 2 = 0

    Since  f(1) = f(2) = 0

    f(x) = 2x4– 6x3 + 3x2 + 3x – 2 is exactly divisible by (x – 1)  and  (x – 2).

    ∴  x2 – 3+ 2  is a factor of  f(x).

     

    Get the complete practice paper by clicking on the following link:

    CBSE Class 9 Mathematics Solved Practice Paper : Set-I

     

     

     

     

     

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