# CBSE Class 9 Mathematics Solved Practice Paper : Set-II

Get here the CBSE Class 9 Mathematics Solved Practice Paper : Set-II. This practice paper has been prepared as per the latest exam pattern to be followed in class 9 annual exams. Every question is provided with an appropriate solution which would give an idea to write perfect answers in the CBSE class 9 Mathematics exam, 2018.

*CBSE Class 9 Maths Practice Paper*

In this article you will get the CBSE Class 9 Mathematics Solved Practice Paper: Set-II. This practice paper has been designed as per the latest exam structure and coveres the whole syllabus of Class 9 Maths.

With the thorough analysis of the CBSE’s examination pattern to be followed in the annual exams, subject experts at jagranjosh has designed this CBSE Class 9 Mathematics Practice Paper which will make you familiar with important questions that will ultimately help you prepare better for the annual exams 2017-2018.

**Structure of CBSE Class 9 Mathematics Solved Practice Paper : Set-II:**

- Includes questions asked from the complete sullabus of CBSE class 9
- Consists of 30 questions divided into four sections A, B, C and D
- Section A contains 6 questions of 1 mark each
- Section B contains 6 questions of 2 marks each
- Section C contains 10 questions of 3 marks each
- Section D contains 8 questions of 4 marks each
- Total marks: 80
- Maximum time: 3 Hours

**CBSE Class 9 Mathematics Examination Pattern 2018**

Solving this practice paper will help you fine tune your prapartion for the final exam letting you know your weak areas which you can recover with more practice and revision.

**Some of the sample questions from CBSE Class 9 Mathematics Solved Practice Paper : Set-II are given below:**

**Q.** Find out the common factor in quadratic polynomials *x*^{2} + 8*x* + 15 and *x*^{2} + 3*x* −10.

**Sol. **

Here, *x*^{2} + 8*x* + 15 = *x*^{2} + 5*x *+ 8*x* + 15 [Splitting the middle term]

= *x*(*x+*5) +3(*x+*5)

= (*x+*3)(*x+*5)

Again, *x*^{2} + 3*x* −10 = *x*^{2} −2*x* + 5*x* −10

= *x*(*x*−2)+5(*x*−2)

=(*x*+5) (*x*−2)

**CBSE Class 9 Mathematics Solved Practice Paper : Set-I**

**Q. **Out of 40 students in a* *9 class, 28 students passes in the annual examination. If a student is selected at random, then find the probability that student has failed in the exam.

**Sol. **

Total number of students = 40

Number of students who passed the examination = 28

Therefore, Number of students failed = 40 − 28 = 12

P(student fail in examination) = 12/40 = 3/10

**Q.** Show that (*x *− 1) is a factor of the polynomial *f*(*x*)=2*x*^{3} − 3*x*^{2} +7*x* − 6.

**Sol.**

Here, *f*(*x*)=2*x*^{3} − 3*x*^{2} +7*x* − 6.

Put, *x* − 1= 0 or *x* = l in *f*(*x*)

Weget: *f*(1) = 2 × 1^{3 }−3 × 1^{2} +7 × 1 − 6

= 2 – 3 + 7 − 6=0

Hence, (*x *− 1) is a factor of the polynomial *f*(*x*).

**Get the complete practice paper by clicking on the following link:**

**CBSE Class 9 Mathematics Solved Practice Paper : Set-II**

Maths is a subject in which students can score full marks by writing appropriate and stepwise solutions to the questions asked in exam paper. But to master this subject an enormous amount of practice is very essential. So, students must solve more and more practice papers to write their exam well and score optimum marks.

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