CBSE Term 2 Class 12 Chemistry Sample Paper 2022 With Answers: Download PDF |CBSE Board Exam 2021-22

CBSE Sample Paper for Class 12th Chemistry for CBSE Term 2 Board Exams 2022 has been released on cbseacademic.nic.in. The direct Download Link for PDF format has been given below and the sample questions along with the marking scheme are discussed here. 

Created On: May 6, 2022 12:14 IST
Modified On: May 6, 2022 12:14 IST
CBSE Board Class 12th Chemistry Sample Paper
CBSE Board Class 12th Chemistry Sample Paper

CBSE Term 2 Class 12 Chemistry Exam would be conducted on May 7,  2022. Check CBSE 12th Chemistry Sample Paper for Term 2 in the article below. This sample paper would be helpful for the students who are to appear for the exams in the year 2020. Also, the students would get to know about the paper patterns and other details of the exam.  Solve this paper before going for the CBSE 12th Chemistry Board Exam Term 2. 

Check the marking scheme along with CBSE Sample paper questions with answers below for the subject of chemistry. 

Term 2- CBSE Class 12 Chemistry Board Exam 2022: Resources, Questions & Answer Writing Tips To Score 90% Marks

CBSE Class 12 Term 2 Exam 2022: Most Important Topics in Physics, Chemistry & Bio| CBSE Board Exams

CBSE 12th Sample Paper 2021-22 For Term 2 Released With CBSE Answers & Marking Scheme 2021-22: Check Here!

CBSE Syllabus (Term 2) Class 12th Chemistry [PDF Download]: CBSE Board Exam 2022

CBSE Term 2 Class 12 Chemistry Sample Paper: Marking Scheme & Paper Pattern

There would be 12 questions in the question paper with internal choice for students. The sections would be divided as follows:

SECTION A - would be very short answer questions carrying 2 marks each.

SECTION B - would be short answer questions carrying 3 marks each.

SECTION C- would be a case-based question carrying 5 marks.

CBSE Term 2 Class 12th Chemistry Sample Paper With Answers:

Answer the following set of questions and find the correct answers below. 

1. Arrange the following in the increasing order of their property indicated:

a. Benzoic acid, Phenol, Picric acid, Salicylic acid (PKA values).

b. Acetaldehyde, Acetone, Methyl tert butyl ketone (reactivity towards NH2OH).

c. Ethanol, ethanoic acid, benzoic acid (boiling point) 

Ans.  (a)Picric acid < salicylic acid < benzoic acid <phenol

(b)Methyl tert – butyl ketone < acetone< Acetaldehyde

(c)ethanol <ethanoic acid < benzoic acid (boiling point of carboxylic acids is higher than alcohols due to extensive hydrogen bonding, the boiling point increases with an increase in molar mass)

2. Solutions of two electrolytes ‘A’ and ‘B’ are diluted. The Λm of ‘B’ increases 1.5 times while that of A increases 25 times. Which of the two is a strong electrolyte? Justify your answer. Graphically show the behaviour of ‘A’ and ‘B’.

Ans. B is a strong electrolyte. The molar conductivity increases slowly with dilution as there is no increase in the number of ions on dilution as strong electrolytes are completely dissociated.  Draw the graph to support the answer. 

Give reasons to support the answer:

a. Presence of Alpha hydrogen in aldehydes and ketones is essential for aldol condensation.

b. 3 –Hydroxy pentan-2-one shows positive Tollen’s test. 

Ans. (a) The alpha hydrogen atoms are acidic in nature due to the presence of the electron-withdrawing carbonyl group. These can be easily removed by a base and the carbanion formed is resonance stabilized.

(b) Tollen’s reagent is a weak oxidizing agent not capable of breaking the C-C bond in ketones. Thus ketones cannot be oxidized using Tollen’s reagent itself gets reduced to Ag. 

4. Account for the following:

a. Aniline cannot be prepared by the ammonolysis of chlorobenzene under normal conditions.

b. N-ethylethanamine boils at 329.3K and butanamine boils at 350.8K, although both are isomeric in nature.

c. Acylation of aniline is carried out in the presence of pyridine.

Ans. a) In the case of chlorobenzene, the C—Cl bond is quite difficult to break as it acquires a partial double bond character due to conjugation. So Under normal conditions, ammonolysis of chlorobenzene does not yield aniline.

b) Primary and secondary amines are engaged in intermolecular association due to hydrogen bonding between the nitrogen of one and hydrogen of another molecule. Due to the presence of three hydrogen atoms, the intermolecular association is more in primary amines than in secondary amines as there are two hydrogen atoms available for hydrogen bond formation in it.

c) During the acylation of aniline, stronger base pyridine is added. This is done in order to remove the HCl so formed during the reaction and to shift the equilibrium to the right-hand side

To check more such questions access the PDF Download Link shared here.

CBSE Chemistry Sample Paper | Term 2 CBSE Board Exams 2021-22

CBSE Chemistry Class 12th Sample Paper solutions | CBSE Board Exams 2021-22

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