Council of Scientific & Industrial Research (CSIR) is going to organize Joint CSIR UGC National Eligibility Test (NET) on 22nd December 2013 in six notified subjects. Jagranjosh.com is providing the sample model paper for the candidates preparing for this exam.
CSIR holds the Joint CSIR-UGC NET twice a year, usually in the month of June and December. And, this is the time for CSIR-UGC NET - December 2013, which is going to be held on 22nd December in the subjects - Chemical Sciences; Earth, Atmospheric, Ocean and Planetary Sciences; Life Sciences; Mathematical Sciences; Physical Sciences; Engineering Sciences.
1. The determinant of an orthogonal matrix of size 5×5 can be:
2. Let y(x) be a solution of the differential equation dy/dx = y2x dy. If y(1) = 1 then y(x) satisfies the equation
1. x2 - 2y + 1 = 0
2. x2 y - 3y + 2 = 0
3. x2 y - 1= 0
4. log(y)/x2 = 0
3. Let S be the sphers x2 + y2 + (z - 1)2 = 9 and F : S - R3 be such that F(x, y, z) = xi + yi + (z - 1)k for all (x, y, z) є S. Let ñ denote the unit outward normal to the surface S. Then the value of the surface integral ∫∫s F. ñ dσ is
Joint CSIR-UGC NET December 2013: Model Papers: Sample Questions of Engineering Sciences
Joint CSIR UGC NET December 2013: Syllabus for All Subjects
Joint CSIR UGC NET December 2013: Exam Scheme
CSIR will issue the list of registered candidates on 20 November 2013 for Joint CSIR UGC NET December 2013 scheduled to be held on 22 December.