[Solved] SSC CHSL 2017 question paper 21Jan2017: Quantitative Aptitude (Evening session)
In this article, we have shared all questions with solutions for SSC CHSL 2016 question paper held on 21Jan2017 in the evening shift. read all questions here
In this article, we have shared all questions with solutions for SSC CHSL 2016 question paper held on 21Jan2017 in the evening shift. These solved questions will give you a perspective of the difficulty level, required time, and methods to solve these questions. Please find these questions here below
Question1  Profit of Rs 936000 has to be divided among three partners Anirudhha, Balwant and Charudatta in the ratio 2:3:5. How much does Charudatta get?
(a) 280800
(b) 187200
(c) 468000
(d) 234000
Ans.:c.
Explanation: Let the share of Anirudha, Balwant, and Charudatta is 2x, 3x, and 5x respectively.
2x + 3x + 5x=936000;
10x= 936000; => x= 93600.
Hence, the amount received by charudatta = 5*93600 = Rs. 468000.
Question 2  The price of an article is cut by 36%, to restore to its original value, the new price must be increased by
(a) 56.25 percent
(b) 36 percent
(c) 26.47 percent
(d) 45 percent
Ans.:a.
Explanation: Suppose, the original price= Rs. x;
Discounted price =Rs. 0.64x;
To restore to its original value % increase= [x0.64x]*100/0.64x = 56.25%
Question 3  The mean of marks secured by 50 students in division A of class X is 61, 25 students of division B is 57 and that of 50 students of division C is 55. What will be the mean of marks of the students of three divisions of Class X?
(a) 57.1
(b) 56.4
(c) 59.2
(d) 57.8
Ans.:d.
Explanation:
Mean of the students of three divisions in Class X= Total marks obtained / Total no. of students;
= [61 * 50 + 25 * 57 + 50 * 55]/ [50 + 25 + 50].
= 7225/125 = 57.8.
Question 4  If the selling price is Rs 1680 after getting a discount of 16%, what was the marked price?
(a) Rs 2000
(b) Rs 1948.8
(c) Rs 1411.2
(d) Rs 1448
Ans.:a.
Explanation: Let Marker price = Rs. x;
Discount price= 0.16x;
x – 0.16x = 1680; => 0.84x = 1680;
x = Rs. 2000;
Question5  The sum of 6xy(2x  4z) , 3yz(2x  3z) and 4xz(3y  2y^{2}) is
(a) 12x^{2}y  6xyz  9yz^{2} + 8xy^{2}z
(b) 12x^{2}y  6xyz + 9yz^{2}  8xy^{2}z
(c) 12x^{2}y  6xyz  9yz^{2}  8xy^{2}z
(d) 12x^{2}y + 6xyz  9yz^{2}  8xy^{2}z
Ans.:c.
Explanation:
= 6xy*(2x  4z) + 3yz*(2x  3z) + 4xz*(3y  2y^{2});
=12x^{2}y – 24xyz + 6xyz – 9yz^{2 }+ 12xyz – 8 xy^{2}z;
= 12x^{2}y  6xyz  9yz^{2}  8xy^{2}z;
Question 6  When a discount of 25% is given on a cruise trip, the profit is 41%. If the discount is 26%, then the profit is
(a) 39.12 percent
(b) 67 percent
(c) 94.88 percent
(d) 11.24 percent
Ans.:b.
Explanation: Suppose, the marked price = Rs. x;
After discount, selling price = 0.75x;
After cutting profit, the purchasing price = Rs. 0.75 * 0.59x = 0.4425x;
Following the condition given in the question
After discount, selling price will be= 0.74x;
% profit = [0.74x – 0.4425x]*100/ 0.4425 = 67.23%.
Question 7  If (cotA  cosecA)^{2} = x, then the value of x is
(a) (1  cosA)/(1 + cosA)
(b) (1  sinA)/(1 + sinA)
(c) (1  secA)/(1 + secA)
(d) (1  cosecA)/(1 + cosecA)
Ans.:
Explanation: x = (cotA  cosecA)^{2};
x = cot^{2}A^{ }+ cosec^{2}A – 2 cotA* cosecA;
Question 8  A does 30% of a work in 30 days. He then calls in B and they together finish the remaining work in 20 days. How long B alone would take to do the whole work?
(a) 40 days
(b) 80 days
(c) 120 days
(d) 20 days
Ans.:a.
Explanation: A’s efficiency = Amount of work done by him/ no. of days;
A’s efficiency = 1 * 30% / 30 days = 1%;
(A+B)’s efficiency = 1 * 70 % / 70 days = 3.5%;
Hence, B’s efficiency = 3.5 %  1% = 2.5%.
No of days taken by B to finish the whole work alone = 1 / 2.5% = 1000/25= 40 days;
Question 9  If 2x  6 ≤ x  3 and 1+3x < 4x + 4, then x can take which of the following values?
(a) 4
(b) 4
(c) 6
(d) 2
Ans.:
Explanation: considering first inference : 2x  6 ≤ x – 3;
= > x ≤ 3;  eq.(i.)
Considering second inference: 1+3x < 4x + 4; = > x > 3;  eq.(ii.)
Considering both equation in mind, x should be equal to 2.
Question 10  If cotA = x, then the value of x is
(a) √(sec^{2}A + 1)
(b) √(cosec^{2}A + 1)
(c) √(sec^{2}A  1)
(d) √(cosec^{2}A  1)
Ans.:d.
Explanation: 1 + cot^{2}A = cosec^{2}A;
Hence, option (d.) will be the correct option.
Question 11  If 14.35  (1.956  x )  83.92 = 3.858 then what is the value of x?
(a) 92.456
(b) 75.384
(c) 71.472
(d) 104.084
Ans.:b.
Explanation: 14.35  (1.956  x )  83.92 = 3.858;
14.35 – 1.956 + x 83.92 = 3.858;
x = 3.858 – 14.35 + 1.956 + 83.92;
x = 75.384;
Question 12  In a Rhombus ABCD, measure of angle CAB is 25°, what is the measure of angle ABC?
(a) 65°
(b) 50°
(c) 40°
(d) 130°
Ans.:
Explanation: if angle CAB = 25^{0}, then angle OBA = 180 – (90 + 25)= 65^{0}.
Since, diagonal bisect the angles in rhombus; hence, angle ABC = 130^{0}.
Question 13  The volume of a cuboid is 320 cubic cm. Find its total surface area if its length and breadth are 10 cm and 8 cm respectively?
(a) 608 sq cms
(b) 304 sq cms
(c) 152 sq cms
(d) 456 sq cms
Ans.:b.
Explanation: Suppose, l = 10 cm and b = 8 cm. Let the height of cuboid = h cm.
Volume of cuboid = l * b* h;
h = 320 / 10*8 = 4 cm.
Total surface area= 2*(lb + bh+ hl);
= 2 * (10*8 + 8 * 4 + 4 * 10) = 304 sq. cm.
Question 14  The circumference of a circle is equal to the perimeter of an equilateral triangle. If the radius of the circle is 7 cm what is the length of the side of the equilateral triangle?
(a) 22/3 cm
(b) 44/3 cm
(c) 44 cm
(d) 22 cm
Ans.:b.
Explanation: suppose, the side of equilateral triangle = a cm.
a = 2*pi*7/3 = 44/3 cm.
Question 15  The slope of the line passing through the points (2,1) and (x,5) is 1. Find x?
(a) 4
(b) 4
(c) 8
(d) 8
Ans.:b.
Explanation: [5 – (1)]/ [x 2] = 1;
x = 4
Question 16  The sum of the ages of father and son at present is 33. Two years ago the product of their ages was 28. What is the age of the father and the son?
(a) 26, 7
(b) 30, 3
(c) 29, 4
(d) 32, 1
Ans.:b.
Explanation: Let the father age is x years, then son’s age = 33 –x.
(x2)* (31x) = 28;
31x –x^{2} 62 + 2x = 28;
x^{2} 33x + 90 =0;
x^{2} 30x 3x + 90 =0;
x(x 30) 3 (x 30) =0; = > x = 3, 30;
Hence, Son’s age = 3 years;
Father’s age = 30 years.
Question 17  Rameshwar goes on a trip on his motorcycle and rides for 405 kms. If he rides for 6 hours at a speed of 45 km/hr, find at what speed he travels for the remaining 3 hours of the journey?
(a) 55 km/hr
(b) 52 km/hr
(c) 45 km/hr
(d) 40 km/hr
Ans.:c.
Explanation: Distance covered in 6 hours= 45*6= 270 kms.
Hence, the remaining speed = (405 270)/3 = 135/3 = 45 kmph.
Question 18  There is 40% increase in an amount in 8 years at simple interest. What will be the compound interest of Rs. 10000 after 3 years at the same rate?
(a) Rs 1576.25
(b) Rs 6222
(c) Rs 7881.25
(d) Rs 4728.75
Ans.:b.
Explanation: Let the principal amount = Rs. x; and interest rate = r%
1.40x = x*r*8/100; = > r = 140/8 = 17.5%;
Question 19  If tan π/3 + cosec π/6 = x, then x is
(a) (1√2)/√2
(b) (√3+4)/2√3
(c) √3+2
(d) (2√21)/2
Ans.:c.
Explanation: put π = 180^{0} in the given equation
x = tan 60 + cosec 30 = 2 + √3
Question 20  If 4x  7y = 3 and 2x  y = 9, then x  y is.
(a) 3
(b) 4
(c) 5
(d) 6
Ans.:a.
Explanation:
4x  7y = 3  eq. (i.)
2x  y = 9  eq. (ii.)
Multiply by 2 in the equation (ii.) and subtract from eq.(i)
5y = 15 = > y=3; and x = 6;
Hence, xy = 3
Question 21  If the length of the side of an equilateral triangle is 6 cm, what is its area?
(a) 18√3 sq cm
(b) 36√3 sq cm
(c) 27√3 sq cm
(d) 9√3 sq cm
Ans.:d.
Explanation:Area of equilateral triangle = √3/4 (side)^{2};
Area of triangle = 9√3 sq. cm.
Question 22 – Refer the below data table and answer the following Question.

Quantity of stock 
Average Cost (Rs) 
Mobile Phones 
99 
15000 
Cameras 
53 
13000 
TVs 
29 
59000 
Refrigerators 
21 
56000 
ACs 
97 
25000 
What is the value of the total stock (in lakh rupees)?
(a) 748.6
(b) 74.86
(c) 168
(d) 299
Ans.:b.
Explanation: Total value of stocks = 99*15000 + 53*13000 + 29*59000 + 21*56000 + 97*25000
= 1485000 + 689000 + 1711000 + 1176000 + 2425000;
=7486000 = 74.86 lakhs
Question 23  Refer the below data table and answer the following Question.
Year 
Ratio Import/Export 
2011 
0.8 
2012 
1.3 
2013 
1 
2014 
1.5 
2015 
0.8 
If the imports in 2012 was Rs. 600 crores and the total exports in the years 2012 and 2013 together was Rs. 4400 cores, then the imports in 2013 was?
(a) 3232
(b) 4622
(c) 3666
(d) 3938
Ans.:d.
Explanation: Export in 2012 = 600/1.3 = 461.53 crores.
Exports (2012 +2013) = 4400 crores.
Hence, export in 2013 = 4400 – 461.53 = 3938.47 crores.
Import in 2013 = 1* 3938.47 = 3938 (rounded off)
Question 24  Refer the below data table and answer the following Question.
Measured on Birthday 
Height of the child (in cms) 
4 
100 
5 
105 
6 
115 
7 
125 
8 
130 
9 
140 
10 
145 
11 
155 
12 
160 
13 
170 
14 
175 
15 
180 
16 
190 
What was the increase in the height of the child from the 10^{th} birthday to the 13^{th} birthday?
(a) 30 cms
(b) 25 cms
(c) 20 cms
(d) 35 cms
Ans.:b.
Explanation: The increment in the height = 170145 = 25cm.
Question 25  Refer the below data table and answer the following Question.
Deep Sleep 
20 
Dreaming 
20 
Light sleep 
30 
Extremely light sleep 
25 
Awake 
5 
Between 10pm to 6am, a fitness band records the following data. How long was the user in Light sleep or in extremely light sleep?
(a) 4.4 hours
(b) 3.9 hours
(c) 2.9 hours
(d) 4.9 hours
Ans.:a.
Explanation:Duration to fall in light sleep or in extremely light sleep = 5 + (5 + 25) + (5 + 25 +30) + (5 + 25 + 30 + 20) + ( 5 + 25 + 30 + 20 + 20)
= 275 = 4.5 hours
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