SSC Exam Reasoning Study Material: A conceptual guide for Puzzle Test

Aug 17, 2016 17:09 IST

SSC is well known for the recruitment of Group ‘B’ and ‘C’ posts under the Ministries/Departments in The Government of India. SSC organizes various examinations like Combined Graduate Level examination, Combine Higher Secondary Level, Stenographer and for SI/DP/CAPF, etc., throughout the year having almost the same Exam Pattern. The Exam paper is comprised of basically 4 subjects.

a. General Intelligence & Reasoning
b. English language & Comprehension
c. Quantitative Aptitude
d. General knowledge

For more detail, click the link given below.

SSC SI, CAPF & ASI Exam 2015: Exam Pattern

https://www.jagranjosh.com/articles/ssc-si-capf-asi-exam-2015-exam-pattern-1427805314-1

SSC Combined Higher Secondary Level (10+2) Exam 2014: Exam Pattern

https://www.jagranjosh.com/articles/ssc-combined-higher-secondary-level-102-exam-2014-exam-pattern-1405771700-1

SSC Stenographer 2016: Take a look of Exam Pattern, Syllabus and Selection Procedure

https://www.jagranjosh.com/articles/ssc-stenographer-2016-take-a-look-of-exam-pattern-syllabus-and-selection-procedure-1464352983-1

So, Jagranjosh.com has introduced a brief plan for revising topics at the time of examination. In this article, Puzzle Test which sometimes appear more difficult to understand in terms of complexity of statements with respect to Time, Relations,Placement Order and other classifications.

Puzzle Test

In the chapter of puzzle test we get questions in the form of puzzles. Broadly there are five types of questions in this topic.

The problems can be classified into the following

(1) Classifications or Categorization

(2) Questions based on Blood Relations

(3) Seating and placing arrangements

(4) Comparison type test

(5) Sequential order of things

(6) Selections based on certain given pre-conditions

1. Classification or Categorization

In this type of test, the questions are based upon the given data belonging to different groups or possessing different qualities. You would be supposed to analyse data by placing the different items or concepts in different categories with the help of given information. These problems can be easily solved by constructing a proper table or chart.

Read the question carefully by keeping in mind every point or detail. It will take a few seconds. After reading the question, you will get the general idea as to what the general theme of the problem is. Determine the usefulness of each of the information and classify all the information into (P) Actual information (Q) Useful secondary information and finally (R) Negative information.

Refer to example given below:

Example ─ Read the following information carefully and answer the questions that follow.

There are six places P, Q, R, S, T and U. There are exactly two district parks, two shopping malls and two amusement parks.

P is not a district park.

Q and T are not shopping malls.

S is not an amusement park.

P and S are not shopping malls.

P and Q are not alike.

1) Which two cities are amusement parks?

a) P and Q
b) T and P
c) R and S
d) Q and U
e) P and S

2) Which two cities are shopping malls?

a) P and C
b) Q and U
c) R and U
d) Q and T
e) P and S

3) Which two cities are district parks?

a) P and Q
b) R and P
c) Q and S
d) P and U
e) None of these

4) Which two cities are neither shopping malls nor district parks?

a) P and Q
b) P and T
c) U and R
d) Q and S
e) None of these

Detailed Explanation:

Step ─ I: The information’s can be analysed in the following manner.

Step ─ II: In the above-mentioned example, we see that first and last sentences have useful secondary information whereas all the remaining has negative information. By studying the second, third, fourth and fifth sentences we put × mark.

We can observe that above table gives some definite information about P and S. P is neither a shopping mall nor a district park. It is, therefore, an amusement park. In the same way, S is neither shopping mall nor amusement park so it must be a district park. We can ü mark at the appropriate places.

Step ─ III: Finally we come to useful secondary information and negative information, for instance P and Q are not alike. This means that Q is not an amusement park. As Q is not a shopping mall, so it must be a district park. Hence, the table will look like this:

Here in the example, there is no negative information about R and U and partly about T. We can assure that R and U are district parks, amusement park and shopping malls and T is amusement park as well as district park.

Step ─ IV: Now in the question it is given that there are exactly two district parks, two shopping malls and two amusement parks. We know the two district parks i.e. Q & S, so we put a × sign on others and then T has to be amusement park. Then we have the two amusement parks i.e. P and T, so we put a  × sign on others. The table will look like this:

Now, U and R have to be Shopping Malls. Hence, our final table is as below:

On the basis of above table, the answers can be drawn.

1. (b) P & T
2. (c) R & U
3. (c) Q & S
4. (b) P & T

2. Comparison Type Test

In such type of questions, comparison of different objects or persons has to be made with respect to one or more qualities. The candidates are required to analyse the information and form either ascending or descending sequence. There may be comparison of heights, marks and age etc.

This can be illustrated through the given example:

i. There is a group of five boys.
ii. Rohit is second in height but younger than Rahul.
iii. Lalit is taller than Pradeep but younger in age.
iv. Rahul and Pradeep are of the same age but Rahul is tallest among them.
v. Sanjay is taller than Lalit and elder to Rahul.

1) If they are arranged in the ascending order of height who will be in third position?

b) Rahul
c) Rohit
d) Sanjay

2) Who is the youngest person in the group?

b) Kamini
d) Rohit
e) Data Inaquate

3) To answer the questions, “Who is the youngest person in group”, which of the given statements is superfluous?

a) Only (i)
b) Only (ii)
c) Only (v)
d) Either (i) or (iv)
e) None of these

We have to determine the sequence of height as well as sequence of age.

By (iii), We have Pradeep < Lalit

By (v), We have Lalit < Sanjay

It is clear that Rahul is the tallest and Rohit is second in height.

Hence, the sequence of height is

Pradeep < Lalit < Sanjay < Rohit < Rahul

For Age sequence

By  (ii) we have Rohit < Rahul

(iii) we have Lalit < Pradeep

(iv) we have Rahul = Pradeep

(v) we have Rahul < Sanjay

There are two possibilities

I is Sanjay < R = Pradeep < Rohit < Lalit

II is Sanjay < R = Pradeep < Lalit < Rohit

1. (d) Clearly, in the increasing order of height Sanjay is in third position.
2. (d) Clearly, in the descending order of ages, Rohit is the youngest person.
3. (a) Clearly I statement is not necessary.

3. Selection Based on Certain Given Pre-conditions

This type of question is solved by keeping in mind various given pre-conditions and a few essential criteria for selection of group items. The candidate has to make the required selection as per the directions given in each question. The best way to solve these questions is through the options.

Example ─
Directions ─ (Q. 1 to 5) Study the following information carefully and answer the questions below.

A team of five is to be selected from amongst five boys P, Q, R, S and T and four girls A, B, C, and D. Some criteria for selection are ─

I. P and D have to be together
II. A cannot be put with C
III. S and B cannot go together
IV. R and T have to be together
V. C cannot be put with Q

1) If two of the members have to be boys, the team will consist of ─

a) PQDPB
b) PSDBC
c) QSDCB
d) RTDAB

2) If C be one of the members, the other members of the team are ─

b) BDPS
c) BDRT
d) DPRT

3) If two of the members are girls and S is one of the members, the members of the team other than S are ─

a) ABQR
b) ABRT

4) If P and R are the members, the other members of the team cannot be ─

a) QTD
b) STD
c) TDA
d) ABT

5) If including A at least three members are girls, the members of the team other than A are ─

a) BDPQ
b) BDQS
c) BDRT
d) CDPS

1. (A) If A is selected naturally S has to be selected.

If B is selected R cannot be selected.

If D is selected Q cannot be selected.

So, the options ADSQR and QD are wrong and RTDCB is not possible because D has to be accompanied with P.

2. (D) If C is selected A cannot be selected, therefore option ADPS is wrong.

S and B cannot go together. So, BDPS is wrong.

S and P have to be together. So, BDRT is wrong. Now, the team combination will be DPRT.

3. (C) If S is selected B cannot be selected. therefore ABQR and ABRT are not correct. D and P have to be always together.

4. (D) If P and R are the members, D and T have to be  selected. Therefore, option (D) ABT is not the correct combination.

5. (A)

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